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3 years ago

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Explain Using the equation for translational kinetic energy, show why a car moving at 40 m/s has four times the translational ki

netic energy of the same car moving at 20 m/s.

1 answer:

djverab [1.8K]3 years ago

7 0

Answer:

Explanation:

Equation for translational kinetic energy = 1/2 m V² where m is mass and V is velocity .

In first case let mass of car be m

Translational kinetic energy = 1/2 m x 40² = 800 m .

In the second case ,

Translational kinetic energy = 1/2 m x 20² = 200 m

So , in former case kinetic energy of car is 4 times that of second case.

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Firdavs [7]

1) See three Kepler laws below

2a) Acceleration is $2.2 m/s^2$

2b) Tension in the string: 27.4 N

3a) Kinetic energy is the energy of motion, potential energy is the energy due to the position

3b) The kinetic energy of the object is 2.25 J

Explanation:

1)

There are three Kepler's law of planetary motion:

1st law: the planets orbit the sun in elliptical orbits, with the Sun located at one of the 2 focii
2nd law: a segment connecting the Sun with each planet sweeps out equal areas in equal time intervals. A direct consequence of this is that, when a planet is further from the sun, it travels slower, and when it is closer to the sun, it travels faster
3rd law: the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit. Mathematically, $T^2 \propto r^3$ , where T is the period of revolution and r is the semi-major axis of the orbit

2a)

To solve the problem, we have to write the equation of motions for each block along the direction parallel to the incline.

For the block on the right, we have:

$M g sin \theta - T = Ma$ (1)

where

$Mg sin \theta$ is the component of the weight of the block parallel to the incline, with

M = 8.0 kg (mass of the block)

$g=9.8 m/s^2$ (acceleration of gravity)

$\theta=35^{\circ}$

T = tension in the string

a = acceleration of the block

For the block on the left, we have similarly

$T-mg sin \theta = ma$ (2)

where

m = 3.5 kg (mass of the block)

$\theta=35^{\circ}$

From (2) we get

$T=mg sin \theta + ma$

Substituting into (1),

$M g sin \theta - mg sin \theta - ma = Ma$

Solving for a,

$a=\frac{M-m}{M+m}g sin \theta=\frac{8.0-3.5}{8.0+3.5}(9.8)(sin 35^{\circ})=2.2 m/s^2$

2b)

The tension in the string can be calculated using the equation

$T=mg sin \theta + ma$

where

m = 3.5 kg (mass of lighter block)

$g=9.8 m/s^2$

$\theta=35^{\circ}$

$a=2.2 m/s^2$ (acceleration found in part 2)

Substituting,

$T=(3.5)(9.8)(sin 35^{\circ}) +(3.5)(2.2)=27.4 N$

3a)

The kinetic energy of an object is the energy due to its motion. It is calculated as

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

The potential energy is the energy possessed by an object due to its position in a gravitational field. For an object near the Earth's surface, it is given by

$U=mgh$

where

m is the mass of the object

g is the strength of the gravitational field

h is the heigth of the object relative to the ground

3b)

The kinetic energy of an object is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the object in this problem,

m = 500 g = 0.5 kg

v = 3 m/s

Substituting, we find its kinetic energy:

$K=\frac{1}{2}(0.5)(3)^2=2.25 J$

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

And about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

7 0

4 years ago

A circular loop of wire 78 mm in radius carries a current of 114 A. Find the (a) magnetic field strength and (b) energy density

Finger [1]

Explanation:

It is given that,

Radius of loop, r = 78 mm = 0.078 m

Current, I = 114 A

(a) Magnetic field strength of the circular loop is given by :

$B=\dfrac{\mu_oI}{2R}$

$B=\dfrac{4\pi \times 10^{-7}\times 114}{2\times 0.078}$

B = 0.000918 T

or

$B=9.18\times 10^{-4}\ T$

(b) Energy density at the center of the loop is given by :

$U=\dfrac{B^2}{2\mu_o}$

$U=\dfrac{(0.000918)^2}{2\times 4\pi \times 10^{-7}}$

$U=0.335\ J/m^3$

Hence, this is the required solution.

7 0

3 years ago

2. An object is dropped from rest. Calculate its velocity after 2.5s if it is dropped:

Alekssandra [29.7K]

Answer:

a=24.5 b=9.5

Explanation:

7 0

3 years ago

A substance that can conduct a current in solution

serious [3.7K]

A substance that can conduct a current in solution is salt.

3 0

3 years ago

Read 2 more answers

Chocolate milk contains more than one type of component. Therefore, it 1 point

crimeas [40]

Answer:

Homogeneous.

Explanation:

Mixture can be defined as a combination of two or more substances present in varied proportion where each materials are distinct and visibly seen by naked eyes.

In Science, there are two (2) main types of mixture and these are;

I. A homogeneous mixture: it can be defined as any liquid, solid or gaseous mixture which has an identical or uniform composition and properties throughout any given sample of the mixture. In Chemistry, all solutions are considered to be a homogeneous mixture. For example, aqueous hydrogen chloride is a homogeneous mixture of water and hydrogen chloride.

II. A heterogenous mixture: it can be defined as any mixture which has a different or non-uniform composition and properties throughout any given sample of the mixture. This ultimately implies that, the constituents of a heterogenous mixture always remain separate in the sample and as such comprises of two or more phases.

Since the chocolate milk contains more than one type of component. Therefore, it is not a homogeneous substance but a heterogenous substance.

6 0

3 years ago