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TiliK225 [7]
3 years ago
9

Which property justifies this statement?

Mathematics
2 answers:
Katen [24]3 years ago
5 0
I know its not division,addition,multiplication,with the process of elimination its reflexive

pashok25 [27]3 years ago
5 0

Answer with Step-by-step explanation:

The Reflexive property states that for every real number x, x=x

Division property states that if a=b and we divide it by any non zero number c then also a/c=b/c

Multiplication property states that if a=b and we multiply it by any number c then also ac=bc

Addition property states that if a=b and we add it by any number c then also a+c=b+c

We are given that x= -6

Adding both sides by 6

⇒ x+6=0

Hence, it justifies the addition property.

Hence, correct option is:

D, Addition

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3х – 8y = — 16<br> =<br> M<br> So yeah I kinda need help
marishachu [46]

Answer:

3x-8y-16  = 0

Step-by-step explanation:

8 0
3 years ago
The length of a rectangle is three times its width. if the area of the rectangle is 75 in2, find its perimeter.
UkoKoshka [18]

Answer:

  40 in

Step-by-step explanation:

For a width of w, the length is 3w and the area and perimeter are ...

  A = LW = (3w)(w) = 3w^2

  P = 2(L+W) = 2(3w +w) = 8w

We are given the area, so we can find w to be ...

  75 in^2 = 3w^2

  25 in^2 = w^2 . . . . . divide by 3

  5 in = w . . . . . . . . . square root

Then the perimeter is ...

  P = 8w = 8(5 in) = 40 in

7 0
3 years ago
Pleade help I will give brainliest
kvv77 [185]

Answer:

1. adjacent

2. vertical

3. vertical

4. neither

5. adjacent

let me know if it's wrong

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th
VMariaS [17]

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

4 0
3 years ago
Nvm <br>I don't need help
Snowcat [4.5K]

Answer:

ok

Step-by-step explanation:

5 0
1 year ago
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