P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
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<span>P(t) = P(0)[exp(-0.0202t)]</span>
All are easy. There is no way to say thatnone way is easier than the other. Well the answer lies in every individual, it depends on which method they are comfortable with. Anyway there are more method to solve quadratic than the listed ones.
Answer: 20.52
Step-by-step explanation:
Your welcome
Step-by-step explanation:
that is only possible, if we don't need to use a 2 and a 5 (but especially the 2) to create the 1 in the middle (log(10) = log(2×5) or log (5×2) = 1).
in other words, if the 1 in the middle is just a given, and does not use any of our digits for is creation, then a solution is possible.
first of all, the upper left corner has to be log(0⁰). we cannot use the digit 0 for anything else. and 0^n (except for n = 0) is not a valid argument for a logarithm.
log(0⁰) = 0 log(2×1) = 0.3... log(9/4) = 0.35...
log(1×2) = 0.3... 1 log(3×6) = 1.26...
log(7/3) = 0.37... log(4×5) = 1.3... log(6⁹) = 7.0...
but as soon as we need to build the center 1 by log(10), which takes then away one of the 2s (as the only way to build 10 by multiplication is 2×5 or 5×2), there is no possible solution.
