Slope-intercept form y = mx + b
where m------> slope
b-------> y-intercept
m= (y1-y2)/(x1-x2)
P1(-3,5) (x1,y1)
P2(2,10) (x2,y2)
m= (5-10)/(-3-2)
m= (-5)/(-5)
m=1
Until now, the equation is y=mx+b
y=1.x+b
y=x+b
But, whe can plug the point P2(2,10) in y =x+b
10 =2 + b
10 - 2 = b
b= 8
Then, the equation is y=mx+b
y= x+8 <-------------------Solution
Verification P1(-3,5) y = x+8 5=-3+8 Ok
P2(2,10) y = x +8 10 = 2+8 Ok
Area of a rectangle = length x width
Standard form : Ax + By = C
y - 4 = 0
y = 4...this is a horizontal line and a horizontal line has a 0 slope
so in standard form, ur equation is : 0x + y = 4
Answer:
0
Step-by-step explanation:
Hi there!
First, find g(4). Notice how on the first given table, when x=4, g(x)=9. Therefore, g(4)=9.
Then, find f(9). Notice how on the second given table, when x=9, f(x)=0.
Therefore, f(g(4)) is equal to 0.
I hope this helps!
Answer: it going to be 10.2% percent
Step-by-step explanation: that how you get your answer as your -
10.2 %
