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jarptica [38.1K]
3 years ago
8

About what fraction of earth's freshwater is in the form of ice

Physics
1 answer:
Bingel [31]3 years ago
3 0
68% So 68/100 of freshwater is found in ice
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Scientists use this part of the electromagnetic spectrum to diagnose broken bones.
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They use x-rays to diagnose broken bones
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How does brainly work i want to get used to this more often.
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do not worry bro you will know how to use it

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Block with mass m =7.6 kg is hung from a vertical spring. when the mass hangs in equilibrium, the spring stretches x = 0.29 m. w
PSYCHO15rus [73]

1) 256.9 N/m

The force applied to the spring is equal to the weight of the block hanging on the spring:

F=mg=(7.6 kg)(9.8 m/s^2)=74.5 N

And the spring constant can be found by using Hook's law, because we know that the displacement caused by this force is x = 0.29 m:

F=kx\\k=\frac{F}{x}=\frac{74.5 N}{0.29 m}=256.9 N/m

2) 1.08 Hz

The angular frequency of oscillation of the spring is given by the formula:

\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{256.9 N/m}{7.6 kg}}=5.81 rad/s

And the frequency of oscillation is given by:

\omega=2\pi f\\f=\frac{2 \pi}{\omega}=\frac{2\pi}{5.81 rad/s}=1.08 Hz

3) 2.19 m/s

The velocity at time t of the block is given by:

v=v_0 cos (\omega t)

where

v_0 = 4.4 m/s is the initial velocity of the block

\omega=5.81 rad/s is the angular frequency

t is the time

Substituting t=0.36 s, we find the speed of the block at that time:

v(0.36 s)=(4.4 m/s) ( cos ((5.81 rad/s)(0.36 s)) = -2.18 m/s

And the negative sign means that the direction of the velocity is upward (because the initial velocity was downward)

4) 25.6 m/s^2

The maximum acceleration is given by:

a_0 = \omega^2 A

where A is the amplitude of the oscillation.

We can find the amplitude by using the law of conservation of energy: in fact, the kinetic energy at the equilibrium point must be equal to the elastic potential energy at the point of maximum displacement:

K=U\\\frac{1}{2}mv_0^2 = \frac{1}{2}kA^2\\A=\sqrt{\frac{mv_0^2}{k}}=\sqrt{\frac{(7.6 kg)(4.4 m/s)^2}{256.9 N/m}}=0.76 m

So, the maximum acceleration is

a_0 = \omega^2 A=(5.81 rad/s)^2 (0.76 m)=25.6 m/s^2

5) 95.1 N

The magnitude of the net force acting on the block is given by the difference between the weight and the restoring force of the spring:

F=mg-kx

First, we need to find the position x at t=0.36 s, which is given by

x(t)=A sin(\omega t)=(0.76 m)(sin ((5.81 rad/s)(0.36 s))=0.66 m

And so, the net force is

F=(7.6 kg)(9.8 m/s^2)-(256.9 N/m)(0.66 m)=-95.1 N

And the negative sign means the direction of the force is upward.

8 0
3 years ago
Read 2 more answers
The diameter of 0-gauge copper wire is 8.252 mm. Find the resistance of a 1.00-km length of such wire used for power transmissio
Dafna1 [17]

Answer:

The value is R = 0.321 \ \Omega

Explanation:

From the question we are told that

   The diameter is  d =  8.252 \  mm  =  0.008252 \  m

    The length of the wire is  l =  1.0 \  km  =  1000 \  m

   Generally the cross sectional area of the copper wire is mathematically represented as

           A  = \pi * \frac{d^2}{4}

=>        A  =  3.142  * \frac{ 0.008252^2}{4}

=>         A  =  5.349 *10^{ - 5} \  m^2

Generally the resistance is mathematically represented as

      R =  \frac{\rho  *  l }{A }

Here \rho is the resistivity of copper with the value  \rho =  1.72*10^{-8} \ \Omega \cdot m

=>    R =  \frac{1.72 *10^{-8}  *   1000 }{5.349 *10^{ - 5}  }

=>    R = 0.321 \ \Omega

5 0
3 years ago
A projectile of mass 100 kg is shot from the surface of Earth by means of a very powerful cannon. If the projectile reaches a he
aksik [14]

Answer:

v = 1.11 \times 10^3 m/s

Explanation:

By energy conservation law we will have

U_i + KE_i = U_f + KE_f

as we know that as the projectile is rising up then due to gravitational attraction of earth it will slow down

At the highest position the speed of the projectile will become zero

So here we will have

-\frac{GMm}{R} + \frac{1}{2}mv^2 = -\frac{GMm}{R+h} + 0

-\frac{(6.67 \times 10^{-11})(5.97 \times 10^{24})(100)}{6.37 \times 10^6} + \frac{1}{2}(100)v^2 = -\frac{(6.67 \times 10^{-11})(5.97 \times 10^{-11})(100)}{(6.37 \times 10^{6} + 65000)}

- 6.25 \times 10^7 + 0.5 v^2 = -6.19 \times 10^7

v = 1.11 \times 10^3 m/s

8 0
3 years ago
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