Answer:
well, the hill isn't constantly going down hill, there's an ending point or goes back up hill making a v/u shape or there's nothing helping the wagon being pushed or pull currently
Explanation:
I think the question should be the below:
<span>What is the total distance, side to side, that the top of the building moves during such an oscillation?
</span>
Answer is the below:
<span>Acceleration .. a = (-) ω² x </span>
<span>(ω = equivalent ang. vel. = 2π.f) (x = displacement from equilibrium position) </span>
<span>x (max) = a(max) /ω² </span>
<span>x = (0.015 x 9.8m/s²) / (2π.f)² .. .. (0.147) / (2π*0.22)² .. .. ►x(max) = 0.077m .. (7.70cm)</span>
Answer:
4.2 x 10⁷N
Explanation:
Given parameters:
Charge on ball:
q₁ = 3C
q₂ = 14C
Distance between balls = 9000m
Unknown:
Force acting on the two balls
Solution:
The force experienced by the two charges is given by coulombs law. It is mathematically expressed as;
F = 
where k = 9 x 10⁹Nm²/C²
q is the charges
r is the distance
Input the variables and solve;
F = 
= 4.2 x 10⁷N
The increase in the average kinetic energy of the ball causes the increase in the temperature of the ball.
Kinetic energy of a particle is directly proportional to its temperature.
A ball initially at rest acquires kinetic energy when an external force is applied to it. As the person strikes the ball with a bat, the ball gains momentum which increases its kinetic energy of the ball.
Temperature on the other hand, is the measure of the average kinetic energy of a particle. Consequently, as the kinetic energy of the ball increases, the temperature of the ball increases as well.
Thus, we can conclude that the increase in the average kinetic energy of the ball causes the increase in the temperature of the ball.
Learn more here: brainly.com/question/18833622
To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as
Here,
q = Charge
t = Time
R = Resistance
C = Capacitance
When the charge reach its half value it has passed 10ms, then the equation is,
We know that RC is equal to the time constant, then
Therefore the time constant for the process is about 14ms
