Answer:
The distance traveled by the woman is 34.1m
Explanation:
Given
The initial height of the cliff
yo = 45m final, positition y = 0m bottom of the cliff
y = yo + ut -1/2gt²
u = 20.0m/s initial speed
g = 9.80m/s²
0 = 45.0 + 20×t –1/2×9.8×t²
0 = 45 +20t –4.9t²
Solving quadratically or by using a calculator,
t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s
So this is the total time it takes for the ball to reach the ground from the height it was thrown.
The distance traveled by the woman is
s = vt
Given the speed of the woman v = 6.00m/s
Therefore
s = 6.00×5.69 = 34.14m
Approximately 34.1m to 3 significant figures.
So that we do not contaminate it with microorganisms or garbage or other human stuff.
Answer:
30 miles
Explanation:
<u>Step 1:</u>
Divide -> 45/60= .75 miles/minute
<u>Step 2:</u>
Multiply -> .75 x 40= 30
Answer:
I am not sure about the answer as I don't have a proper calculator besides me now
Explanation:
but I used this equation:
(8.20)sin30(1-d)=10d
Idk whether it is correct or not, I'm just a student too
what is your method of doing this question?
c .... work is force x distance as a definition
