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KengaRu [80]
4 years ago
5

Which statement is true?

Physics
2 answers:
sineoko [7]4 years ago
7 0
Heya!!!

Answer to your question:
Gravity is the force of attraction between two objects with mass and is dependent on the distance between these objects.

Formula for gravitational force is: GMm/r^2

where M is the mass of planet, m is the mass of object and r is the distance between them.

Hope it helps ^_^
Gnesinka [82]4 years ago
5 0
Gravity is the force of attraction between two objects with mass.  
Its strength depends on the mass of both masses, and on the
distance between them.
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A chamber 5.0 cm long with flat, parallel windows at the ends is placed in one arm of a Michelson interferometer (see below). Th
Ivahew [28]

Answer:

1.00029

Explanation:

A wave is a disturbance which travels through a medium and transfers energy without displacing the medium itself.

interference is one of the characteristics of a wave motion

The Michelson interferometer produces interference fringes by splitting a beam of monochromatic light so that one beam strikes a fixed mirror and the other a movable mirror. When the reflected beams are reflected, an interference pattern results.

∝Δm=Δud

∝=wavelength  500nm

Δm=number of fringes

d=length 9f the  Michelson interferometer chamber

Δu= change in refractive index

500*10^-9*29=0.05*Δu

Δu=0.00029

REFRACTIVE INDEX=1+0.00029

refractive index=

1.00029

6 0
3 years ago
The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency diffe
mel-nik [20]

Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?

B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?

Answer:

The frequency change percentage is 9.94%

Explanation:

The frequency shift can be calculated as follows.

F= \frac{V+V_{0}}{V+V_{s}}

   = 9.05GHz\times\frac{343m/s+0}{343m/s+(-31.3m/s)}

   =9.95 GHz

So the frequency change seen by the detector is 9.95 - 9.05

% difference= \frac{0.9}{9.05} \times100

                    = 9.94%

3 0
3 years ago
Select all the correct answers.
Sergeu [11.5K]
Force is transferred from the moving ball to the stationary ball.
8 0
3 years ago
Read 2 more answers
According to x-ray observations, the space between galaxies in a galaxy cluster is?
crimeas [40]

According to x-ray observations, the space between galaxies in a galaxy cluster is very hot. It is because the matter between galaxies (often called the intergalactic medium) is mostly hot, ionized hydrogen with bits of heavier elements such as carbon, oxygen and silicon thrown in.

Massive structures are collapsing than at earlier times. Large collapsing structures lead to higher velocity intergalactic shocks and, as a result, significant intergalactic shock heating, with some gas heated well above the 10^{4} K temperatures.

Heating also occurs as galaxies expel out most of the gas that fell into them. The final product is a warm/hot phase, with temperatures of > 10^{5} K.

Now, Let's know how do you use X-rays to make space observations?

X-radiation is absorbed by the Earth's atmosphere, so instruments to detect X-rays must be taken to high altitude by balloons, sounding rockets, and satellites.

To learn more about Galaxy Cluster, here

brainly.com/question/16557484

#SPJ4

6 0
2 years ago
In 1610, galileo used his telescope to discover four prominent moons around jupiter. their mean orbital radii a and periods t ar
katrin2010 [14]

Time period of any moon of Jupiter is given by

T = 2\pi \sqrt{\frac{r^3}{GM}}

from above formula we can say that mass of Jupiter is given by

M = \frac{4 \pi^2 r^3}{GT^2}

now for part a)

r = 4.22 * 10^8 m

T = 1.77 day = 152928 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (4.22 * 10^8)^3}{(6.67 * 10^{-11})(152928)^2}

M = 1.9* 10^{27} kg

Part B)

r = 6.71 * 10^8 m

T = 3.55 day = 306720 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (6.71 * 10^8)^3}{(6.67 * 10^{-11})(306720)^2}

M = 1.9* 10^{27} kg

Part c)

r = 10.7 * 10^8 m

T = 7.16 day = 618624 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (10.7 * 10^8)^3}{(6.67 * 10^{-11})(618624)^2}

M = 1.89* 10^{27} kg

PART D)

r = 18.8 * 10^8 m

T = 16.7 day = 1442880 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (18.8 * 10^8)^3}{(6.67 * 10^{-11})(1442880)^2}

M = 1.889* 10^{27} kg

6 0
3 years ago
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