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Lina20 [59]
2 years ago
11

abraham has 16 blue marbles and 18 rwd marbles. if he wamts to place them in identical groups without any marbles left over

Mathematics
1 answer:
VladimirAG [237]2 years ago
8 0

Answer:

If Abraham divides them into 2 separate groups, he should have 17 marbles on each group.

Step-by-step explanation:

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The answer is 3 because x is -7. I hope this helps!
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Use the table to find the ratio. Enter the ratio as a fraction in simplest form.
Lady bird [3.3K]

Answer:

7/16

Step-by-step explanation:

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3 years ago
What value of x makes this statement true?<br><br> 3x = 2x+12
saul85 [17]

Answer:

x=12

Step-by-step explanation:

3x=2x+12

3x-2x=12

x=12

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2 years ago
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Follow the directions to solve the system of equations by elimination. 8x + 7y=39 4x – 14y = -68​
harina [27]

Step-by-step explanation:

Hey there!

Here;

The equations are;

8x + 7y = 39.......(i)

4x - 14y =  - 68..........(ii)

Multiplying equation (i) by 2.

16x + 14y = 78

<u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>4</u><u>y</u><u> </u><u> </u><u> </u><u>=</u><u> </u><u>-68</u>

20x = 10

x =  \frac{10}{20}

x = 1/2.

Putting value of 'x' in equation (i).

8 \times  \frac{1}{2}  + 7y =  39

4 + 7y = 39

7y = 3 9 - 4

y =  \frac{35}{7}

Therefore the value of y is 5.

<u>Check</u><u>:</u>

<u>Put</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>and</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>(</u><u>i</u><u>)</u><u>.</u>

8x + 7y = 39

8 \times  \frac{1}{2}  + 7 \times 5 = 39

4 + 35 = 39

39 = 39

(True).

<u>Therefore</u><u>, </u><u>the</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>;</u><u> </u><u>(</u><u>1</u><u>/</u><u>2</u><u>,</u><u>5</u><u>)</u><u>.</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
3 years ago
(4x + 4)(ax – 1) – x2 +4
Oksana_A [137]

Answer:

b=-3

Step-by-step explanation:

If the expression simplifies to bx that means the x^{2} terms and the constant terms must be cancel out.

Simplify it first.

(4x+4)(ax-1)-x^{2} +4\\=(4ax^{2} -4x+4ax-4)-x^{2} +4\\=4ax^{2} -x^{2} -4x+4ax-4+4\\=4ax^{2} -x^{2} -4x+4ax

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the x^{2} terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

4ax^{2} -x^{2} =0\\x^{2} (4a-1)=0\\4a-1=0\\4a=1\\a=\frac{1}{4}

If we put a = ¼, then we can find the value of b:

=4(\frac{1}{4} )x^{2} -x^{2} -4x+4(\frac{1}{4} )x\\=x^{2} -x^{2} -4x+x\\ (cancel out x^{2} terms)\\

=-3x

bx=-3x\\      if the  expression is equivalent to bx

Therefore, b = –3.

8 0
3 years ago
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