3 years ago

URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its

Physics

1 answer:

lara31 [8.8K]3 years ago

4 0

Answer:

Explanation:

because the speed divide by the frequency is equal to the wavelength(in meters)

5×10² m

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20 Points available for physics help

Sonja [21]

The second one is correct not sure about the first one sorry

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A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise

kiruha [24]

Answer:

$h_m=25.8\ m$

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

$\displaystyle h_m=\frac{v_o^2}{2g}$

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

$\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}$

$\mathbf{h_m=25.8\ m}$

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3 years ago

How to determine the position of the center of mass.

Rus_ich [418]

Answer:

The center of mass can be calculated by taking the masses you are trying to find the center of mass between and multiplying them by their positions

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3 years ago

In the waves lab, you changed ____ to see how it would affect wave speed.

ikadub [295]

Hi there!

I believe the answer is transversal or transverse.

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3 years ago

When the displacement in SHM is equal to 1/4 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b

Anna71 [15]

Answer:

$\frac{KE}{TE} = \frac{15}{16}$

$\frac{U}{TE} = \frac{1}{16}$

Explanation:

Let the amplitude of SHM is given as A

so the total energy of SHM is given as

$E = \frac{1}{2}kA^2$

now we know that

kinetic energy is given as

$KE = \frac{1}{2}k(A^2 - x^2)$

here

$x = \frac{A}{4}$

so now we have

$KE = \frac{1}{2}k(A^2 - \frac{A^2}{16})$

$KE = \frac{15}{32}kA^2$

now its fraction with respect to total energy is given as

$\frac{KE}{TE} = \frac{15}{16}$

Potential energy is given as

$U = \frac{1}{2}kx^2$

so we have

$U = \frac{1}{32}kA^2$

so fraction of energy is given as

$\frac{U}{TE} = \frac{1}{16}$

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3 years ago