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Solnce55 [7]
2 years ago
12

URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its

Physics
1 answer:
lara31 [8.8K]2 years ago
4 0

Answer:

A

Explanation:

because the speed divide by the frequency is equal to the wavelength(in meters)

5×10² m

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Answer:

One 200 is bigger than 100

Explanation:

6 0
3 years ago
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How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?
Akimi4 [234]

Answer:19.5 m

Explanation:

Given

coefficient of kinetic Friction \mu _k=0.10

Initial speed u=3.9\ m/s

Friction is present so it tries to stop to the object and stops it completely after moving certain distance let say s

maximum deceleration provided by friction is

a_{max}=\mu _k\cdot g

a_{max}=0.1\times 3.9=0.39\ m/s^2

using equation of motion

v^2-u^2=2 as

where v=final\ velocity

u=initial velocity

a=acceleration

s=displacement

(0)-(3.9)^2=2\times (-0.39)\times s

s=19.5\ m

6 0
3 years ago
A light ray travels inside a horizontal plate of glass, striking its upper surface at an angle of incidence of 50°. This ray is
MAXImum [283]

Answer:

n₂ = 1.15

Explanation:

Given,

Angle of incidence,θ₁ = 50°

refractive index of the glass,n₁ = 1.50

refractive index of liquid = ?

For largest refractive index angle of refraction should be equal to 90°.

Using Snell's law

n₁ sin θ₁ =  n₂ sin θ₂

1.50 x sin 50° =  n₂ sin 90°

n₂ = 1.15

Hence, refractive index of the liquid is equal to 1.15.

5 0
3 years ago
What impulse results if the force acting on an object is described by the force-time graph shown?
Hoochie [10]
The correct answer to this question is "2.1 kgm/s." The impulse results if the force acting on an object that is described by the force-time graph shown is that 2.1 kgm/s. Based on the graph, it shows like a plateau with the flat at the force of 2.1 N.
8 0
3 years ago
Two light bulbs, A and B, are connected to a 120-V outlet (a constant voltage source). Light bulb A is rated at 60 W and light b
d1i1m1o1n [39]

Answer:

Bulb A has a greater resistance.

Explanation:

Electric power (P) = V²/R

P = V²/R................ Equation 1

Where P = power, V = Voltage, R = Resistance.

Make R the subject of the equation

R = V²/P ................ Equation 2

For Bulb A,

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

For bulb B

Given: V =120 V, P = 100 W.

Substitute into equation 2

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Hence Bulb A has a greater resistance.

5 0
3 years ago
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