Question

A bell with a fundamental frequency of 880 Hz is moving toward an observer at 3.5 m/s. If the speed of sound is 343 m/s, what pitch would be heard by the observer?

Answer 1

Answer:

f = 889 Hz

Explanation:

As we know that when observer and source move relative to each other

Then in that case the frequency heard by the observer is different from actual frequency

The changed in the frequency is given as

$f = f_0(\frac{v}{v - v_s})$

now we know that

v = 343 m/s

$v_s = 3.5 m/s$

$f_0 = 880 Hz$

now we have

$f = 880(\frac{343}{343 - 3.5})$

$f = 889 Hz$