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3 years ago

What is the velocity of a rocket if it travels a distance of 2400 m in 3 s?

Physics

1 answer:

SOVA2 [1]3 years ago

6 0

Answer:

v = 800 m/s

Explanation:

Given that,

Distance, d = 2400 m

Time, t = 3 s

We need to find the velocity of a rocket. Distance covered per unit time equals velocity. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{2400\ m}{3\ s}\\\\v=800\ m/s$

So, the velocity of the truck is 800 m/s.

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Một tải có điện trở R = 19ohm đấu vào nguồn điện một chiều có E = 100V,

klio [65]

Answer:

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Explanation:

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2 years ago

a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of

Anarel [89]

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

-4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

$F_t$ -W = m a

Whera $F_t$ is the trampoline force

Body weight is

W = mg

We substitute

$F_t$ - mg = ma

a = $\frac{F_t - m g}{m}$

Let's calculate

a = $\frac{375 - 75 \ 9.8 }{75}$

a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

-4.8 m / s²

Learn more here: brainly.com/question/19860811

7 0

2 years ago

A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of th

lana [24]

Answer:

a. $\displaystyle k_o=1350\ J$

b. $\displaystyle k_1=0\ J$

c. $\Delta k=-1350\ J$

d. $W=-1350\ J$

e. $F=-675\ N$

Explanation:

<u>Work and Kinetic Energy </u>

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

$\Delta k=k_1-k_0$

Knowing that

$\displaystyle k=\frac{mv^2}{2}$

We have

$\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

The work done by the force who caused the change of velocity (acceleration) is

$\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

If we know the distance x traveled by the object, the work can also be calculated by

$W=F.x$

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

$\displaystyle k_o=\frac{mv_0^2}{2}$

$\displaystyle k_o=\frac{(75)6^2}{2}$

$\boxed{\displaystyle k_o=1350\ J}$

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

$\displaystyle k_1=\frac{(75)0^2}{2}$

$\boxed{\displaystyle k_1=0\ J}$

c. The change of kinetic energy is

$\Delta k=k_1-k_0=0\ J-1350\ J$

$\boxed{\Delta k=-1350\ J}$

d. The work done by friction to stop the player is

$W=\Delta k=k_1-k_0$

$\boxed{W=-1350\ J}$

e. We compute the force of friction by using

$W=F.x$

and solving for x

$\displaystyle F=\frac{W}{x}$

$\displaystyle F=\frac{-1350\ J}{2\ m}$

$\boxed{F=-675\ N}$

The negative sign indicates the force is against movement

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2 years ago

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2 years ago

What is the total charge of 1.0g of electrons?

Serhud [2]

<span>1.0 gram (g) of electrons would contain 10^27 electrons Electrons have an electric charge of −1.602×10−19 coulomb so total charge of 1 g electrons = -1.602 x 10^-19 x 10^27 = -1.602 x 10^8</span>

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2 years ago