What is the velocity of a rocket if it travels a distance of 2400 m in 3 s?
1 answer:
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Answer:
E = 1.38 x 10⁸ eV = 138 MeV
Explanation:
The energy associated with the given wavelength can be found from the following formula:
where,
E = Energy of electron = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = Speed of Light = 3 x 10⁸ m/s
λ = wavelength = 9 fm = 9 x 10⁻¹⁵ m
Therefore,
<u>E = 1.38 x 10⁸ eV = 138 MeV</u>
Explanation:
you can see this example to undersranding the question
Answer:
Speed: 4.8 m/s
Velocity: 4.8 m/s north
Explanation:
Definitions:
- Speed is a scalar quantity, which is equal to the ratio between distance covered (d) and time taken (t):
- Velocity is a vector quantity, whose magnitude is equal to the ratio between the displacement of the object and the time taken:
And it also has a direction (the same as the displacement).
In this problem:
- The object travels a distance of
d = 105 m
In a time interval of
t = 22 s
So its speed is
- The displacement of the object is the same as the distance in this case, so still 105 m, covered in a time interval of 22 s; this means that the magnitude of the velocity is the same as the speed:
However, velocity is a vector quantity, so it also has a direction: and since the object has moved north, the direction of the velocity is north as well.