Question

You pull a block of mass m across across a frictionless table with a constant force. you also pull with an equal constant force a block of larger mass m. the blocks are initially at rest. if you pull the blocks through the same distance, which block has the greater kinetic energy, and which block has the greater momentum, respectively?

Answer 1

For any mass m:

a = F/m
v = √2*F/m*s = √2F/sm = k/√m
Momentum = mv = k√m
Energy = 1/ mv² = 1/2 m.k²/m = 1/2k²

SO
Both will have same energy
The larger mass will have greater momentum