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Reil [10]
3 years ago
11

A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c

ar is acting in the same direction as its motion. How much work has the car done?
Physics
1 answer:
Reika [66]3 years ago
8 0
When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.

a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s

Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
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dezoksy [38]
I think your in the wrong section kid. This should be in Earth and Space Science.
7 0
3 years ago
A box is placed on a table. If an upward pulling force on the box is slightly less than the weight of the box, what will happen
aniked [119]

Answer:

<u><em>A for certain.</em></u>

Explanation:

I got it right on the test, thanks to the other brainly answerer teresecaway. But knowing the answer doesnt help much if you dont know WHY. The reason WHY is as follows. At first you might think it would be B, because the downwards force is greater than the upwards force. I thought that maybe upwards force would also count as the table supporting it, but no, thats just structural inanimate solid table. The answer is A. gravity would have to be HIGHLY raised or somebody pressing down on it, to make it fall through the table.

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3 years ago
What is the acceleration of a 24 kg mass pushed by a 6N force?
olga nikolaevna [1]
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hope this helps x
7 0
3 years ago
A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer
dlinn [17]
<h2>Answer:7.14ms^{-1},4.125ms^{-1}</h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let v be the total velocity.

Given that,v=8.25ms^{-1}

We call the horizontal velocity as v_{h} and the vertical velocity as v_{v}.

v_{h}=vCos\alpha

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It is given that \alpha =30^{0}

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7 0
4 years ago
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bixtya [17]

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Explanation:

6 0
3 years ago
Read 2 more answers
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