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Veseljchak [2.6K]
3 years ago
10

If Na was to form a 2 ion, from what orbital subshell would the second electron be lost?

Chemistry
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

2p

Explanation:

Sodium has an atomic number of 11, thus, the neutral atom has 11 electrons. The electron configuration is:

Na: 1s² 2s² 2p⁶ 3s¹

To gain stability, it loses an electron from its outer shell to form the cation Na⁺. Its electron configuration is:

Na⁺: 1s² 2s² 2p⁶

If it were to lose a second electron to form a Na²⁺ cation, the electron should be lost from the 2p orbital subshell and its electron configuration would be:

Na²⁺: 1s² 2s² 2p⁵

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4 0
2 years ago
A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62
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6 0
3 years ago
If 20 grams of N2 react completely with H2 , how many moles of NH3 are produced? Show Work
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This is the balanced eq
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first you need to find mole of N2 by using
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it is N2:NH3
1:2
0.7138:0.7138×2
0.7138:1.4276 moles
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5 0
4 years ago
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