<h3><u>Answer;</u></h3>
No ions present
<h3><u>Explanation;</u></h3>
- Ionic compounds are compounds made up of ions. These ions are atoms that gain or lose electrons, giving them a net positive or negative charge.
- Atoms that gain electrons and therefore have a net negative charge are known as anions. Conversely, atoms that lose electrons have a net positive charge are called cations.
- C12H22O11 (sucrose) is not an ionic compound, and therefore does not have any ions. Sucrose is a molecular compound.
Answer:
temperature of the water
Explanation:
Density is defied as mass divided by the volume. To investigate how the density of water change with temperature, Bob have the change the temperature and read the volume and mass of the investigated sample.
Even if there is a different salt content between booted water or tap water and have an influence on the density (compared with pure water), this difference is not so big so the change in density with temperature can be determined. Considering that the experiment do not require extreme accuracy, any type of water may be used (bottled water of tap water).
We have that the name (not chemical symbol) of the main group element in period 5 and group 3A is
Metalloid boron (B)
From the Question we are told that
The element belongs to
Period 5 and group 3A
Generally
Group 3A of the periodic table includes the metalloid boron (B), aluminum (Al), indium (In), and thallium (Tl) gallium (Ga),
Period 5 is possessed by the metalloid boron (B) of the Group 3A
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Answer:
Molar concentration of S₂ is 1.77×10⁻⁶M
Explanation:
For the reaction:
2H₂S(g) ⇄ 2H₂(g) + S₂(g)
The equilibirum constant, K, is defined as:
![K = \frac{[S_2][H_2]^2}{[H_2S]^2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BS_2%5D%5BH_2%5D%5E2%7D%7B%5BH_2S%5D%5E2%7D)
<em>(1)</em>
Concentrations in equilibirum are:
[H₂S] : 0,163/0.500L - X
[H₂] : 0,0500/0.500L + X
[S₂] : X
Replacing the concentrations and the equilibrium value in (1):
![K = \frac{[X][0.1+X]^2}{[0326-X]^2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BX%5D%5B0.1%2BX%5D%5E2%7D%7B%5B0326-X%5D%5E2%7D)
1.67x10⁻⁷ = X (X² + 0.2X + 0.01) / (X² -0.652X + 0.106)
1.67x10⁻⁷X² - 1.09x10⁻⁷X + 1.77x10⁻⁸ = X³ + 0.2X² + 0.01X
0 = X³ + 0.2X² + 0.01X - 1.77x10⁻⁸
Solving for X:
X = 1.77×10⁻⁶
As [S₂] = X, <em>molar concentration of S₂ is 1.77×10⁻⁶M</em>
I hope it helps!
