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Alex17521 [72]
3 years ago
12

What is the nuclear binding energy of an atom that has a mass defect of 5.0446

Chemistry
2 answers:
Lynna [10]3 years ago
7 0

Answer:

There is no answer that meets the final value of energy.

Maybe C. And you mistakenly put the 3 at the end.

Explanation:

Albert Einstein's equation of spatial relativity is the well-known E = mc2, which means that the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) at square. Einstein argued that the mass of a body is a measure of its energy content.

Now, if we know the mass of an atom, it is possible to find its energy.

  • m = (5.0446 * 10) ∧-29 kg
  • c = (3.00 * 10) ∧8 m / s
  • E = 5.0446 * 10∧-29 kg * ((3.00x10∧8 m / s) ∧2)

E = 4.54 x10∧-12 k * m∧2 * s∧2

- Knowing that kg * m∧2 * s∧2 is the same as Joules then:

<u>E = 4.54 x10∧-12 J</u>

notsponge [240]3 years ago
4 0

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

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fgiga [73]

Answer:

The correct answer is B.

Explanation:

The molecule of water has 2 atoms of hydrogen and 1 atom of oxygen.

The ratio of masses are given as:

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This illustrates the law of definite proportions which is also known as law of constant compositions .

The law states that 'the elements combining to form compound always combine in a fixed ratio by their mass.'

Whereas :

Law of multiple proportion states that when two elements combine with each other to form more than one compounds , the mass of one element with respect to the fixed mass of another element are in ratio of small whole numbers.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

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(will give brainliest) show your work. How many grams of Copper(I) nitrate, CuNO3 are required to produce 88.0 grams of aluminum
ValentinkaMS [17]

Based on the stoichiometry of the reaction, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

<h3>What is stoichiometry of a reaction?</h3>

The stoichiometry of a reaction is the molar ratio in which reactants combine to form products.

The stoichiometry of the reaction shows that 6 moles of copper (i) nitrate produces 2 moles of aluminium nitrate.

molar mass of Copper(I) nitrate, CuNO3 = 126 g

molar mass of aluminum nitrate, Al(NO3)3 = 213 g

88.0 g of aluminum nitrate, Al(NO3)3 = 88.0/213 moles = 0.413 moles

0.413 moles of Al(NO3)3 will be produced by 0.413 ×6/3 = 1.239 moles of CuNO3

Mass of 1.239 moles of CuNO3 = 1.239 × 126 = 156.114 g of CuNO3

Therefore, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

Learn more about stoichiometry at: brainly.com/question/16060223

Therefore, 156.114 g of CuNO3

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Answer:

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Explanation:

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The third problem would be the same steps as the second one.

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