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Alex17521 [72]
3 years ago
12

What is the nuclear binding energy of an atom that has a mass defect of 5.0446

Chemistry
2 answers:
Lynna [10]3 years ago
7 0

Answer:

There is no answer that meets the final value of energy.

Maybe C. And you mistakenly put the 3 at the end.

Explanation:

Albert Einstein's equation of spatial relativity is the well-known E = mc2, which means that the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) at square. Einstein argued that the mass of a body is a measure of its energy content.

Now, if we know the mass of an atom, it is possible to find its energy.

  • m = (5.0446 * 10) ∧-29 kg
  • c = (3.00 * 10) ∧8 m / s
  • E = 5.0446 * 10∧-29 kg * ((3.00x10∧8 m / s) ∧2)

E = 4.54 x10∧-12 k * m∧2 * s∧2

- Knowing that kg * m∧2 * s∧2 is the same as Joules then:

<u>E = 4.54 x10∧-12 J</u>

notsponge [240]3 years ago
4 0

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

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What is the mass in 6.34x10^23 molecules of calcium chloride
Liono4ka [1.6K]

Answer : The mass of calcium chloride is, 116.84 grams

Solution : Given,

Molar mass of calcium chloride, CaCl_2 = 110.98 g/mole

Number of molecules of calcium chloride = 6.34\times 10^{23}

As we know that,

1 mole of calcium chloride contains 6.022\times 10^{23} molecules of calcium chloride

or,

1 mole of calcium chloride contains 110.98 grams of calcium chloride

Or, we can say that

As, 6.022\times 10^{23} molecules of calcium chloride present in 110.98 grams of calcium chloride

So, 6.34\times 10^{23} molecules of calcium chloride present in \frac{6.34\times 10^{23}}{6.022\times 10^{23}}\times 110.98=116.84grams of calcium chloride

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3 years ago
Consider the following balanced equation:
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<span>Zn⁰ + 2H⁺ ------> Zn²⁺ + H2⁰

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Zinc has a specific heat capacity of 0.390 J/goC. What is its molar heat capacity? Enter your answer numerically to three signif
ch4aika [34]

Answer:

The answer to your questions is  Cm = 25.5 J/mol°C  

Explanation:

Data

Heat capacity = 0.390 J/g°C

Molar heat capacity = ?

Process

1.- Look for the atomic number of Zinc

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2.- Convert heat capacity to molar heat capacity

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3 years ago
A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to
grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

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with mass of water = 125 grams

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with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

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C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0
3 years ago
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