Basically, like this:
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Answer:
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
Explanation:
Let the cost for ribeye steak dinners be m and cost for grilled salmon dinners be n.
A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day.
So, we have
10 m + 18 n = 590.39 -------equation 1
Another day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49
So, we have
22 m + 9 n = 583.49 -------equation 2
equation 2 x 2
44 m + 18 n = 1166.98 -------equation 3
equation 3 - equation 1
44 m + 18 n - ( 10 m + 18 n ) = 1166.98 - 590.39
m = 16.96 $
Substituting in equation 1
22 x 16.96 + 9 n = 583.49
n = 23.37 $
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
X - y = 7.....x = y + 7
x * y = 60
y(y + 7) = 60
y^2 + 7y = 60
y^2 + 7y - 60 = 0
(y + 12)(y - 5) = 0
y + 12 = 0
y = -12....not this one because it is negative
y - 5 = 0
y = 5 <===
x - y = 7
x - 5 = 7
x = 7 + 5
x = 12 <==
so ur 2 numbers are 12 and 5
Answer:
B=![\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's do the multiplication AB.
If A=![\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!
