Answer:
y = 14
Step-by-step explanation:
Plug in 4 as x into the equation:
y = 2 + 3x
y = 2 + 3(4)
Simplify:
y = 2 + 12
y = 14
So, when x = 4, y = 14.
2(7÷10)×1÷3+4÷15=1.4×0.33+0.267
=0.462+0.267
=0.729(0.73)
I used a Venn Diagram which I attached.
Think of it as a flower and work your way from the center out to the doubles (two kinds of coffee) and finally the singles (only one kind of coffee)
I place 4 in the center to represent the people that like all three.
Then I put 8 in the Latte Espresso group since they along with the 4 who like all three, make up the 12 who like lattes and espresso. I put 4 in the Latte & Cappuccino group since they and the 4 who like all coffees, make up the 8 who like lattes and cappuccinos. And then I put 5 in the Espresso Cappuccino group who along with the 4 in the middle make up the 9 who like both of those.
In all 20 like lattes and my latte circle already has 16 so I added 4 (who only like lattes). 22 like espresso and I have accounted for 17 (8+4+5) so that means there are 5 who only like espresso. Finally out of the 17 who like cappuccinos, 13 are already accounted for so I will add 4 who like only cappuccinos.
Since there are 50 people and I can account for 34 of them (add all the numbers in all three circles), there must be 50-34 people who don't like any. The correct answer is
d.16
It is b because if thats your numbers and u divide weight by inches and times it by the diameter you get your answer
Answer:
0.04,0.25.0.52
Step-by-step explanation:
Given that you throw a dart at a circular target of radius 10 inches.
Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,
probability that the dart falls
(a) within 2 inches of the center
Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches
Prob = 
(b) within 2 inches of the rim.
For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches
Prob= 
c) within I quadrant
area of I quadrant / area of circle=0.25
d) within I quadrant and within 2 inches of the rim
= I quadrant area + 2 inches ring area - common area
= 
