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3 years ago

Answer this I need help

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

The data is

8,9,9,10,12,12,13,14,15,15,15,16,18,19,20

There are 15 data points

The median is the 15/2 = 7.5 rounding to 8

The 8th data point

8,9,9,10,12,12,13, 14, 15,15,15,16,18,19,20

Take the 7 points on the left and divide in half

8,9,9, 10 ,12,12,13, 14, 15,15,15, 16, 18,19,2

The interquartile range is the middle of the upper half of the data minus the middle of the lower half of the data

16 - 10 = 6

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Andre45 [30]

Answer:

The volume is 356 $in^3$ , which agrees with the second answer option listed.

Step-by-step explanation:

Recall that the volume of a pyramid is the product of the area of its base(B) times the pyramid's height (h), divided by three:

$V=B*\frac{h}{3}$

For our case, the area of the base "B" is the area of a square of side = 8 inches. That is the area B is:

$B=(8 \,in)^2=64\,in^2$

Now we can include this value and the value of the pyramid's height (h=12 in) in the formula for the volume to give the answer:

$V=B*\frac{h}{3}=64\,in^2\,\frac{12\,in}{3} =256\,in^3$

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Find the LCM between the denominators.

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