Answer:
The angle between the polarization direction of the eye and the polarization direction of the incident light = 56.1°
Explanation:
For polarization, the relationship between the intensity of transmitted rays (I), intensity of incident rays (I₀) and the angle between the polarization direction of the eye and the polarization direction of the incident light (θ) is given as
I = I₀ cos²θ
I = intensity of transmitted rays = 263 W/m²
I₀ = intensity of incident rays = 845 W/m²
θ = ?
263 = 845 cos²θ
cos²θ = (263/845) = 0.3112
Cos θ = √0.3112 = 0.5579
θ = cos⁻¹ (0.5579)
θ = 56.1°
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Answer:
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The Ohm's law is I(the strength of the current flowing in a conductor)= V(the potential difference applied to the ends) divided by R(resistance)
Answer:
<em>D. Velocity</em>
Explanation:
<u>Energy Dimensional Analysis</u>
The kinetic energy (K) can be calculated by the formula:
Where:
m = mass of the object
v = speed at which the object moves
Solving for v:
Or, equivalently:
In dimensional terms, the quotient of the square roots of the energy and the mass is equivalent to the dimensions of the velocity (or speed),
D. Velocity
