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Stells [14]
3 years ago
7

What is the ohms law

Physics
1 answer:
Anton [14]3 years ago
4 0
The Ohm's law is I(the strength of the current flowing in a conductor)= V(the potential difference applied to the ends) divided by R(resistance)
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A cruise ship sails due south at 2.50 m/s while a coast guard patrol boat heads 19.0° north of west at 4.80 m/s. What are the x-
Nesterboy [21]

Answer:

Explanation:

We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .

velocity of cruise ship

Vcs = - 2.5 j

Vpb =  - 4.8 cos 19 i + 4.8 sin 19 j = - 4.54 i + 1.56 j

velocity of the cruise ship relative to the patrol boat

= Vcs - Vpb

=  - 2.5 j - ( - 4.54 i + 1.56 j  )

=  - 2.5 j  +  4.54 i -   1.56 j  

= 2.04 i - 1.56 j .

x-component of the velocity of the cruise ship relative to the patrol boat

= 2.04 m /s

y-component of the velocity of the cruise ship relative to the patrol boat

= - 1.56 m /s .

7 0
3 years ago
It is harmful to settle near the airport why
Gemiola [76]
Yes, plane accidents can happen near you, it can harm your property and cause a disaster.
4 0
2 years ago
How much heat energy must be added to the gas to expand the cylinder length to 16.0 cm ?
Lapatulllka [165]

This question is incomplete, the complete question is;

A monatomic gas fills the left end of the cylinder in the following figure. At 300 K , the gas cylinder length is 14.0 cm and the spring is compressed by65.0 cm . How much heat energy must be added to the gas to expand the cylinder length to 16.0 cm ?

Answer:

the required heat energy is 16 J

Explanation:

Given the data in the question;

Lets consider the ideal gas equation;

PV = nRT

from the image, we calculate initial pressure;

Pi = ( 2000N/M × 0.06m) / 0.0008 m²

Pi = 15 × 10⁴ Pa

next we find Initial velocity

Vi = (0.0008 m²)(0.14) = 1.1 × 10⁻⁴ m²

now we find the number of moles

n = [(15 × 10⁴ Pa)(1.1 × 10⁻⁴ m²)] / 8.31 J/molK × 300K

N = 6.6 × 10⁻³ mol

next we calculate the final temperature;

Pf = ( 2000N/m × 0.08) / 0.0008 m²

Pf = 2 × 10⁵ Pa

Calculate the final Volume

Vf = (0.0008 m² × 0.16 m = 1.28 × 10⁻⁴ m³

we also determine the final temperature

T_{f} =  (2 × 10⁵ Pa × 1.28 × 10⁻⁴ m³) / 6.6 × 10⁻³ × 8.31 J/molK

T_{f}  = 466.8 K

so change in temperature ΔT

ΔT =  466.8 K - 300K = 166.8 K

we then calculate the change in thermal energy

ΔU = nCΔT

ΔU = ( 6.6 × 10⁻³ mol ) × 12.5 × 166.8K

ΔU = 13.761 J

C is the isochoric molar specific heat which is equal to 3R/2 for monoatomic

now we calculate the work done;

W = 1/2 × K( x_{i\\}² - x_{f\\}² )

W = 1/2 × ( 2000 N/m) ( 0.06² - 0.08² )

= - 2.8 J

and we then calculate the heat energy using the following expression;

Q = ΔU - W

we substitute

Q = 13.761 - (- 2.8 J)

Q = 13.761 + 2.8 J)

Q =  16 J

Therefore, the required heat energy is 16 J

5 0
3 years ago
Lake Baikal in Siberia has a maximum depth of 1642 m. What is the water
Veseljchak [2.6K]

Explanation:

Fluid gauge pressure is:

P = ρgh

where ρ is the fluid density and h is the depth of the fluid.

P = (1000 kg/m³) (9.8 m/s²) (1642 m)

P = 16,091,600 Pa

Rounded to four significant figures, the gauge pressure is 16.09 MPa.

3 0
3 years ago
a farmer lifts a bale of hay that is 12m off the ground . If he uses a force of 350 n, how much work does the farmer do?
hjlf

Answer:

4200 Joules

Explanation:

Work done =force x distance

From the question , we’re given f =350N ,

d = 12m

Using the above formula, we have

Workdone = 350 x 12

= 4200 Joules

5 0
3 years ago
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