Answer:
a) The schematic illustrating is attached
b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ
c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ
Explanation:
b) The heat transfer to the engine and the heat transfer from the engine to the air is:
Where
W = 750 kJ
n = 35% = 0.25
Replacing:
c) The efficiency of Carnot engine is:
The heat transfer to the heat engine is:
The heat transfer from the heat engine is:
Foolish, ambiguous question, with no correct answer, but at a wild guess, it MIGHT wobble about it own axis????
Electromagnetic would be the weakest interaction of nature.
If it produces 20J of light energy in a second, then that 20J is the 10% of the supply that becomes useful output.
20 J/s = 10% of Supply
20 J/s = (0.1) x (Supply)
Divide each side by 0.1:
Supply = (20 J/s) / (0.1)
<em>Supply = 200 J/s </em>(200 watts)
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Here's something to think about: What could you do to make the lamp more efficient ? Answer: Use it for a heater !
If you use it for a heater, then the HEAT is the 'useful' part, and the light is the part that you really don't care about. Suddenly ... bada-boom ... the lamp is 90% efficient !
Answer:
oK so here's <u>what you should do is add .09 and 0.6</u>
Explanation:
