Answer:
Final speed of the train is 7.5 m/s
Explanation:
It is given that,
Uniform acceleration of the train is, a = 1.5 m/s²
It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :
Here, train starts from rest so, u = 0
v = 7.5 m/s
So, the final velocity of the train is 7.5 m/s. Hence, this is the required solution.
Answer:
1. Current is usually the flow of <u>electrons</u>.
Explanation:
The flow of charges through a wire or conductor is called electric current.
Kinetic energy<span>is the </span>energy<span> of body or a system with respect to the motion of the body or of the particles in the system. </span>Potential energy<span> is the stored </span>energy<span> in an object of system because of its position or configuration.</span>
From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.
We need to find its height.
We will use the formula P.E = mgh
Therefore h = P.E / mg
where P.E is the potential energy,
m is mass in kg,
g is acceleration due to gravity (9.8 m/s²)
h is the height of the object's displacement in meters.
h = P.E. / mg
h = 14000 / 40 × 9.8
h = 14000 / 392
h = 35.7
Therefore the canon ball was 35.7 meters high.
Answer: d constint speed
Explanation: im 15 and no the answer
