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s2008m [1.1K]
3 years ago
13

What is the volume of the box pictured below?

Mathematics
1 answer:
noname [10]3 years ago
4 0

Answer:

\frac{3}{4} m³

Step-by-step explanation:

The volume (V) of the cuboid is calculated as

V = lbh ( l is length, b is breadth and h is height ) , then

V = 1 \frac{1}{8} × \frac{4}{5} × \frac{5}{6} ( change mixed number to improper fraction )

  = \frac{9}{8} × \frac{4}{5} × \frac{5}{6} ( cancel the 5's, 4 and 8 by 4 and 9 and 6 by 3 )

  = \frac{3}{2} × \frac{1}{1} × \frac{1}{2}

  = \frac{3}{4} m³

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Graph y = 2x + 3 A? B? C? OR D
alexandr402 [8]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Can someone answer this asap :))
poizon [28]
For graphing make sure to shade the right portion and to make the line dotted like (— — — —)
the red is y>8x-4, the blue is y>-1/2x+1/2

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multiply each side by 4:
8x-y < 4
add y to each side:
8x < 4+y
subtract 4 from each side:
8x-4 < y
rewrite:
y > 8x-4

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3 years ago
Please I NEED HELP ASAP <br>Graph the system of equations 2x+y=5; 14+7y=35
Luden [163]
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5 0
4 years ago
Read 2 more answers
A soccer ball is kicked and modeled by the function h(x)=-0.0085x²+0.25x+6, where h is the height of the ball in feet and x is t
torisob [31]

Answer:

8 ft

Step-by-step explanation:

h(x)=-0.0085x²+0.25x+6,

The maximum height will be at the vertex

The x coordinate is at

h = -b/2a  where b is the x term coefficient and a is the x^2 term coefficient

h = -(.25)/(2(-.0085)

   =14.70588235

We want to find the height so we need to substitute this into the equation

h(14.70588235)=-0.0085(14.70588235)^2+0.25(14.70588235)+6,

                          =-1.838235294+3.676470588+6

                          =7.838235293 ft

To the nearest foot

                            = 8 ft

5 0
3 years ago
Read 2 more answers
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

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\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
4 years ago
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