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aniked [119]
3 years ago
14

Think about Newton's 2nd Law, Force equals mass times acceleration. Liz puts a 1 kg weight and a 10 kg weight on identical wagon

s. She then applies a 10N force to each wagon. What will be true about the acceleration of the bottom wagon that has more mass?
Question 16 options:
1 The acceleration of the bottom wagon will be greater.
2 The acceleration of the bottom wagon will be smaller.
3 The bottom wagon will accelerate the same amount as the top one.
Physics
2 answers:
Sonja [21]3 years ago
7 0

The acceleration of the bottom wagon will be greater. hope it helps TR3way

Alexeev081 [22]3 years ago
5 0
More force is needed for more mass. Therefore, if the mass is greater and the force is not enough then the object will less likely accelerate
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An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about _____ years.
Airida [17]

Answer:

An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about  2 years.

Explanation:

Given;

orbital period of 3 years, P = 3 years

To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.

Kepler's third law;

P² = a³

where;

P is the orbital period

a is the orbital semi-major axis

(3)² = a³

9 = a³

a = a = \sqrt[3]{9} \\\\a = 2.08 \ years

Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about  2 years.

5 0
3 years ago
Suppose humans have weights which are normally distributed with mean 170 lbs and SD 50 lbs. If 400 humans are selected at random
MrRa [10]

Answer:

 P(x< 175)= 0.9772

Explanation:

given,

mean weight of human = μ = 170 lbs

standard deviation = SD = 50 lbs

N = 400 humans

By using central limit theorem,

P (x< 175)

P(x< 175)= P(z

P(x< 175)= P(z

P (x< 175)= P(z

P (x< 175)= P(z

using z-table

 P (x< 175)= 0.9772

hence, the probability that total weight is less tan 175 lbs is equal to

 P(x< 175)= 0.9772

7 0
3 years ago
Two identical soccer balls are rolled toward each other. What will be true after they collide headon? (2 points)
elixir [45]

Complete Question:

Two identical soccer balls are rolled toward each other. What will be true after they collide headon?

Group of answer choices.

A. they will both stop rolling immediately after they collide head–on.

B. One ball will stop rolling and the other will roll backward at a slower speed.

C. They will both roll back at the same speed they had before the collision

D.They will both roll to the side at a faster speed after the collision

Answer:

C. They will both roll back at the same speed they had before the collision

Explanation:

Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.

This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.

In this scenario, two identical soccer balls are rolled toward each other. Thus, after they collide headon, they will both roll back at the same speed they had before the collision in accordance with Newton’s Third Law of Motion.

Additionally, The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

This ultimately implies that, if the two identical soccer balls exert forces only on each other, their total momentum is conserved

5 0
3 years ago
the gas in a balloon has T=280 K and V=0.0279 m^3. if the temperature increases to 320 K at constant pressure, what is the new v
8_murik_8 [283]

Answer:

Charles law explains that volume is directly proportional to temperature

Explanation:

  1. u would equate V1/T1=V2/T2
  2. U are looking for V2 since u already have V1 , T1 and T2
3 0
3 years ago
We know the moon circulates the Earth. Suppose the mass of the Earth and moon are 5.9742 x1024 kg and 7.36 x 1022 kg, whereas th
algol [13]

Answer:

The gravitational force between two objects, one of mass M1 and the other of mass M2, is:

F = G*M1*M2/R^2

Where G is a constant:

G = 6.6x10^11 m^3*/(kg*s^2)

And R is the distance between the two objects.

M1 = 5.9742x10^24 kg

M2 = 7.36x10^22 kg

R = 382171 km = 382171000 m

Then the gravitational force is:

F = 6.6x10^-11 m^3*/(kg*s^2)*(5.9742x10^24 kg)*(7.36x10^22 kg)/(382171000 m)^2

F = 1.987x10^20 N

4 0
4 years ago
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