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3 years ago

Ill mark as brainliest

Physics

1 answer:

Elis [28]3 years ago

8 0

Answer: 30Ω

Explanation:

Given that,

Electrical potential (V) = 120V

Current drawn (I) = 4A

Effective resistance of your computer (R) = ?

Recall that voltage is the product of current and resistance

i.e V = I x R

120V = 4A x R

R = 120V / 4A

R = 30Ω (The unit of resistance is ohms, and its symbol is Ω)

Thus, the effective resistance of your computer is 30Ω

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One star is emitting primarily visible light and another star is emitting primarily infrared light. which star is hotter?

Leona [35]

The star that would be hotter would be; the star emitting visible light.

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4 years ago

A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it atta

Jobisdone [24]

Answer: The correct answer is option b.

Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.

The acceleration of the rocket is $99.0m/s^2$

To calculate the distance of rocket, we use third equation of motion, which is:

$v^2-u^2=2as$

where, v = final velocity = 445m/s

u = initial velocity = 0m/s

a = acceleration = $99m/s^2$

s = distance = ? m

Putting values in above equation, we get:

$(445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters$

3 0

3 years ago

A charged capacitor is connected to an ideal inductor to form an LC circuit with a frequency of oscillation f = 1.6 Hz. At time

IrinaK [193]

Answer:

$8.0\mu C$

Explanation:

We are given that

$f=1.6 Hz$

$q=3.0\mu C=3.0\times 10^{-6} C$

$1\mu C=10^{-6} C$

Current,I= $75\mu A=75\times 10^{-6} A$

$1\mu A=10^{-6} A$

We have to find the maximum charge of the capacitor.

Charge on the capacitor, $q=q_0cos\omega t$

$\omega=2\pi f=2\pi\times 1.6=3.2\pi rad/s$

$3\times 10^{-6}=q_0cos3.2\pi t$ ....(1)

$I=\frac{dq}{dt}=-q_0\omega sin\omega t$

$75\times 10^{-6}=-q_0(3.2\pi)sin3.2\pi t$ ....(2)

Equation (2) divided by equation (1)

$-3.2\pi tan3.2\pi t=\frac{75\times 10^{-6}}{3\times 10^{-6}}=25$

$tan3.2\pi t=-\frac{25}{3.2\pi}=-2.488$

$3.2\pi t=tan^{-1}(-2.488)=-1.188rad$

$q_0=\frac{q}{cos\omega t}=\frac{3\times 10^{-6}}{cos(-1.188)}=8.0\times 10^{-6}=8\mu C$

Hence, the maximum charge of the capacitor= $8.0\mu C$

4 0

4 years ago

What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4

mrs_skeptik [129]

Answer:

$x = 2\sqrt 2$

Explanation:

Given

$Hypotenuse = 4$

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

$x^2 + x^2 = 4^2$ --- i.e. the other legs are equal

So, we have:

$2x^2 = 16$

Divide both sides by 2

$x^2=8$

Take square roots of both sides

$x = \sqrt 8$

Simplify

$x = 2\sqrt 2$

5 0

3 years ago

Read 2 more answers

A 5 kg box is sliding across a level floor. The box is acted upon by a force of 27 newtons east and a frictional force of 17 new

Juliette [100K]

Answer:

The acceleration of the box is 2.

Explanation:

According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.

Net force = Mass × Acceleration

So $Acceleration = \frac{Net force}{Mass}$

Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.

Net force = 27-17 = 10 N.

Thus, $Acceleration = \frac{10 N}{5 kg}$

So 2 $m/s^{2}$ is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.

5 0

4 years ago