The launch speed of a horizontally launched projectile is 13.28 m/s.
<h3>
Time of motion of the projectile</h3>
The time of motion is calculated as follows;
t = √(2h / g)
where;
- h is height of the cliff
- g is acceleration due to gravity
t = √(2 x 19.3 / 9.8)
t = 1.98 s
<h3>Launch speed of the projectile</h3>
X = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
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Answer:
2.67 seconds
i dont have an explanation
Answer:
The force the rock exerts on Sarah =#is 65 N
Explanation:
The given parameters are;
Sarah's weight = 392 N
The force with which Sarah pushes the rock = 65 N
The mass of the rock = 56 kg
The weight of the rock = The mass of the rock × Acceleration due to gravity
∴ The weight of the rock = 56 kg ×9.81 m/s² = 549.36 N
Given that the force Sarah applies to push the rock = 65 N, then by Newton's third law of motion which states that action and reaction are equal and opposite, the force that the rock exert on Sarah is equal an opposite to the force Sarah is applying
Therefore, the force the rock exerts on Sarah = 65 N (in the opposite direction).
Answer:
D: The distance between the particles decreases
Explanation:
Taking away energy slows down molecules, like how you slow down when you are cold (I think)
