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coldgirl [10]
3 years ago
14

Is work required to pull a nucleon out of an atomic nucleus? Does the nucleon, once outside the nucleus, hove more mass than it

had inside the nucleus?
Physics
1 answer:
olga2289 [7]3 years ago
6 0
<span>Work is required to pull a nucleon out of an atomic nucleus. It has more mass outside the nucleus.</span>
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After a water had boiled, the temperature of the water decreases by 22degrees. The mass of the water in the kettle is 0.50kg.The
kifflom [539]

<u>Answer</u>

46,200 J

The energy of given out when a substance is losing heat is given by:

H = mcΔθ

Where m is the mass of the substance,

            c is the specific heat capacity of the substance and

           Δθ is the temperature change.

H = 0.50 × 22 4200

  = 46,200 Joules.

4 0
4 years ago
The rate at which speed changes is called
pochemuha

Answer:

Acceleration

Explanation:

I think so & hope it will help yuh!

8 0
3 years ago
Please help me with questions 1, 2 and 3. <br> i need a step by step explanation
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Answer:

1) d

2) 5 m/s

3) 100

Explanation:

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1) Solve equation (ii) for acceleration a and plug the result in equation (i)

(iii) a = \frac{v -v_0}{t}

(iv) x = \frac{v-v_0}{2t}t^2+v_0t + x_0

Simplify equation (iv) and use the given values v = 0, x₀ = 0:

(v) x=-\frac{v_0}{2}t + v_0t= \frac{v_0}{2}t

2) Given v₀= 3m/s, a=0.2m/s², t=10 s. Using equation (ii) to get the final velocity v:v=at+v_0=0.2\frac{m}{s^2} * 10s+3\frac{m}{s}=2\frac{m}{s}+3\frac{m}{s}=5\frac{m}{s}

3) Given v₀=0m/s, t₁=10s, t₂=1s and x₀=0. Looking for factor f = x(t₁)/x(t₂) using equation(i) to calculate x(t₁) and x(t₂):

f=\frac{x(t_1)}{x(t_2)}=\frac{\frac{1}{2}at_1^2 }{\frac{1}{2}at_2^2}=\frac{t_1^2}{t_2^2}=\frac{10^2}{1^2}=\frac{100}{1}

5 0
3 years ago
Please answer I will give good rating and mark brainlest
lina2011 [118]
The answer is C. You must divide your wavelength and your frequency to get your answer.
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The sun, moon, planets and stars rise in the ____ and set in the ____.
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The sun, moon, planets and stars rise in the EAST and set in the WEST.
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