Is work required to pull a nucleon out of an atomic nucleus? Does the nucleon, once outside the nucleus, hove more mass than it
1 answer:
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By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
(1)
where
is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
. The radius of the wire is half the diameter:
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
where
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire:
Answer:
v = 4.4 m / s
Explanation:
Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.
Starting point. Point A
Em₀ = K + U = ½ m v2 + mg y_a
point B.
Em_f = U = m g y
the energy is conserved
Em₀ = Em_f
½ m v² + mg y_a = m g y
½ m v² = m g (y -y_a)
v =
In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m
v =
v = 4.4 m / s