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coldgirl [10]
4 years ago
14

Is work required to pull a nucleon out of an atomic nucleus? Does the nucleon, once outside the nucleus, hove more mass than it

had inside the nucleus?
Physics
1 answer:
olga2289 [7]4 years ago
6 0
<span>Work is required to pull a nucleon out of an atomic nucleus. It has more mass outside the nucleus.</span>
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A water skier lets go of the tow rope upon leaving the end ofa
ANTONII [103]

Answer:

1.35m

Explanation:

At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.

The vertical speed at the jumping point can be computed:

v_v^2 + v_h^2 = v^2

v_v^2 + 13^2 = 14^2

v_v^2 = 196 - 169 = 27

v_v = \sqrt{27} = 5.2 m/s

When the skier jumps to the its potential energy is converted to kinetic energy:

E_p = E_k

mgh = mv_v^2/2

where m is the skier mass and h is the vertical distance traveled, v_v is the vertical velocity at jumping point, and h is the highest point.

Let g = 10m/s2

We can divide both sides of the equation by m:

gh = v_v^2/2

h = \frac{v_v^2}{2g} = \frac{27}{2*10} = 1.35 m

3 0
3 years ago
A 0.1 kg bouncy ball moves toward a brick wall with a speed of 11 m/s. After colliding with the wall, the ball travels at a spee
mr_godi [17]
Impulse is change in momentum.  The initial momentum was
0.1kg*11m/s=1.1kg m/s.
The second momentum is 0.1*(-8.8m/s)=-0.88 (since it's moving backward now)
The difference is P1-P2 = 1.1-(-0.88)=1.98kg m/s
4 0
4 years ago
What does a tree do to maintain homeostasis during the winter months?
grin007 [14]

Answer:

During dormancy, a tree's metabolism, energy consumption, and growth all slow down significantly in order to endure the harsh season of winter when water and sunlight are more scarce.

Explanation:

hope it helps

mark me brainliest pls

6 0
3 years ago
How can "Ali" distinguish the interference patterns produced by diffraction gratings from the interference patterns produced by
I am Lyosha [343]

Answer:

The interference pattern from a diffraction grating will have a wide, central bright band with alternate dark and bright bands on both sides, and the interference pattern will have an equally spaced dark and bright band.

Explanation:

In diffraction pattern we know that the distance between two consecutive minimum position is maximum

So here position of minimum is given as

asin\theta = N\lambda

now we have central maximum is of maximum width while all other have width of decreasing order.

While when we use Young's double slit pattern then we can say that position of all maximum and minimum intensity on the screen will be at same distance.

so here we have

y = \frac{N\lambda L}{d}

so all the maximum and minimum intensity will have equal width.

3 0
3 years ago
Which type of star cluster forms from tightly packed groups or older stars ?
Igoryamba
The answer is globular :)
3 0
3 years ago
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