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vlada-n [284]
3 years ago
7

What happens when a force exerted on an object cause the object to move?

Physics
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

B. Kinetic energy is created

Explanation:

sergey [27]3 years ago
3 0
The answer is B kinetic energy is created
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Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.3 cm . Two of
sweet [91]

Answer:

1.44\times 10^{-3} N

Explanation:

We are given that three charged particle are placed at each corner  of equilateral triangle.

q_1=-8.2 nC,q_2=-16.4 nC,q_3=8.0nC

q_1=-8.2\times 10^{-9} C

q_2=-16.4\times 10^{-9} C

q_3=8.0\times 10^{-9} C

Side of equilateral triangle =3.3 cm=\frac{3.3}{100}=0.033m

We know that each angle of equilateral angle=60^{\circ}

Net force=F =\sum\frac{kQq }{d^2}

Where k=9\times 10^9 Nm^2/C^2

If we bisect the angle at q_3 then we have 30 degrees from there to either charge.

Direction of vertical force  due to charge q_1 and q_2

Therefore, force will be added

Vertical  force=9\times 10^9\times q_3(q_1+q_2)\frac{cos30}{(0.033)^2})

Vertical net force=9\times 10^9\times 8\times 10^{-9}(-8.2-16.4)\times 10^{-9}\times 10^6\times\frac{\sqrt3}{2\times 1089}

Vertical  force =9\times 8(-24.6)\times 10^{-9}\times 10^6\times 1.732\times \frac{1}{2178}

Vertical  force=-1.41\times 10^{-3}N (towards q_1}

Horizontal component are opposite in direction then will b subtracted

Horizontal force=9\times 10^9\times 8\times 10^{-9}(-8.2+16.4) \times 10^{-9}\times \frac{sin30}{(0.033)^2}

Horizontal force=0.27\times 10^-3} N(towards q_2

Net electric force acting on particle 3 due to particle =\sqrt{F^2_x+F^2_y}

Net force=\sqrt{(-1.41\times 10^{-3})^2+(0.27\times 10^{-3})^2}

Net force=1.44\times 10^{-3} N

3 0
3 years ago
I need the answers ASAP.
dsp73

Answer:

Explanation:

A) <em>Large</em>: As she opens her parachute, she begins to displace a large volume of air. This leads to a Large air resistance

B) <em>increase, weight</em>: As she falls, the air resistance force <u><em>increases</em></u>. Now there is a force acting in opposite directions to her <u><em>weight.</em></u>

C)<em>Weight, Decelerate:</em> The skydiver has only the downward force of her <u><em>weight</em></u> pulling down on her, so she starts to <u><em>decelerate</em></u>

D) <em>Weight, Upward, Resultant</em>:

Her <u><em>weight </em></u>is now equal to the <u><em>upward </em></u>force from the ground. Her <u><em>resultant  </em></u>force is then zero

E) <em>Increases, same, constant,  resultant, terminal</em>:

As she accelerates faster, the air resistance force <u><em>increases</em></u>. It is now the <u><em>same </em></u>as her weight. She now moves at a <u><em>constant</em></u> speed because the <u><em>resultant </em></u>force acting on her is zero. She is now at her <u><em>terminal </em></u>velocity.

F) <em>Increases, same, constant, terminal</em>:

As she decelerates, the air resistance force on her parachute <u><em>increases </em></u>until it is the <u><em>same</em></u> as her weight. She is now moving with a <u><em>constant </em></u>speed until she hits the ground - a new slower <u><em>terminal</em></u> velocity

4 0
2 years ago
A small sphere with mass 5.00.×10−7kg and charge +3.00μC is released from rest a distance of 0.400 m above a large horizontal in
julia-pushkina [17]
I will assume you are asking what the initial acceleration of the sphere is since the information provided seems to indicate that.
First we need to know Newton's Law
F=ma.  
We know the mass of the sphere and we want a so we solve to get
a=F/m.
Now we need the force on the charged sphere.  This is given by the electric field, E and the charge, Q.  The relationship is F=Q×E.  (Recall that the electric field units can be expressed in Newtons/Coulomb).
Now the electric field above a large (~infinite) sheet of charge with a known charge density σ, is given by
E = σ/(2ε0)
Plug in your values of σ, to get E, then the sphere charge Q to get F, the the mass into a = F/m to get the acceleration

6 0
3 years ago
Which example best illustrates the transfer of energy between two waves?
FromTheMoon [43]

Answer:

A) A buoy rises in the water as a boat speeds past.

Explanation:

The passing boat transfers energy in the form of a wave. Other options illustrate other physics concepts like gravity (falling egg) or Newton's law (for every action, there is an equal and opposite reaction).

7 0
3 years ago
Give me 1 example of complete inelastic collision​
Allisa [31]

i hope it helped thanks

4 0
2 years ago
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