How much charge must pass by a point in a wire in 10 s for the current inb the wire to be 0.50 a?
1 answer:
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When you drop an object from some height on the spring objects initial potential energy is converted to kinetic energy, this kinetic energy is then used to compress the spring. Once all the energy is used the spring stops compressing and starts oscillating.
We need to find how much the spring compressed in both cases.
From the above analysis, we can conclude that potential energy in the gravitational field has to be equal to the potential energy of compressed spring.
We solve for x (in our case h=1):
Now we just have to plug in the numbers:
We need to find how much the spring compressed in both cases.
From the above analysis, we can conclude that potential energy in the gravitational field has to be equal to the potential energy of compressed spring.
We solve for x (in our case h=1):
Now we just have to plug in the numbers:
Answer:
E = 1.1 10⁶ N / C
Explanation:
In this case they indicate that we can approximate the membrane as a parallel plate capacitor, we can use
E =
note that in this case the electric field created by each plate goes in the same direction, they are added
let's calculate
E =
E = 1.1 10⁶ N / C