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2 years ago

If a swimmer is swimming 200m at 4 m/s how long would it take them to complete the race

Physics

2 answers:

DENIUS [597]2 years ago

7 0

Answer:

An intermediate swimmer would probably take about four to five minutes, while a trained swimmer could take less than three. The world record is 1:42:00, held by Paul Biedermann. If you are a good swimmer you would swim it easily in 3 and a half minutes.

Explanation:

bonufazy [111]2 years ago

4 0

Distance=200m
Speed=4m/s

$\\ \sf\longmapsto Speed=\dfrac{Distance}{Time}$

$\\ \sf\longmapsto Time=\dfrac{Distance}{Speed}$

$\\ \sf\longmapsto Time=\dfrac{200}{4}$

$\\ \sf\longmapsto Time=50s$

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A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm

Mashutka [201]

Answer:

$a = 0.53 m/s^2$

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

$\omega = 2\pi f$

$\omega = 2\pi ( \frac{20}{60})$

$\omega = 2.10 rad/s$

so final tangential speed is given as

$v = r\omega$

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3 years ago

Please help :/ The same motor is used in rockets with different masses. The rockets have different accelerations. According to N

Ymorist [56]

Answer:

1. As rocket mass increases, acceleration decreases.

2. The inverse of the mass of the boat.

Explanation:

1. Newton's second law of motion states;

F = ma

where F is the force applied, m is the mass and a is the acceleration.

Therefore, increasing the mass of a rocket increases its weight which would reduce its acceleration provided that the force is constant. Thus, as rocket mass increases, acceleration decreases.

2. The slope of the graph can be expressed as;

From Newton's second law,

F = ma

Slope = (Δa) ÷ (ΔF)

Slope = $\frac{a}{F}$

⇒ $\frac{1}{m}$ = $\frac{a}{F}$

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3 years ago

A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?

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The cliff is 319. kilograms above the water

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