Any number from 21-98 is between 20 and 99.
Answer:
The answer is 429 = 3×11×13.
Step-by-step explanation:
You have to divide by prime number :
429 ÷ 3 = 143
143 ÷ 11 = 13
13 ÷ 13 = 1
Answer:
The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.7291
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have
. So



The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Let S=larger square side and s=smaller square side. The area between the larger and smaller is simple the larger area minus the smaller area. The area of any square being s^2. So our remaining area is:
A=S^2-s^2
A=144-49=95 cm^2
The dimensions would be 29 by 29.
To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.
Dividing the perimeter by the number of sides, we have
116/4 = 29
This means that both length and width can be 29.