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Rufina [12.5K]
3 years ago
13

Please help me asap! pleaseee

Mathematics
2 answers:
Nady [450]3 years ago
7 0
The answer is b = 26
lina2011 [118]3 years ago
4 0
It’s B 26 in a rhombus opposite sides are parallel
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Derivative of -3x^2+4x
RideAnS [48]
-6x + 4

Looking at the first term we know it's the power times the base to the power of to the original minus one.
(-3x×2)^(2-1) = -6x
Then the second term would just be the leading coefficient 4.
7 0
3 years ago
4) Solve for x: 4(2x - 10) = 12x + 10
Lera25 [3.4K]

Answer:

x=-25/2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
a comedy show sells lower level tickets for $78 and upper level tickets for $59. on the opening knight 2368 tickets were sold fo
shusha [124]
Let L represent lower level tickets and U upper level.

Starter equations:
L + U = 2368
78L + 59U = 157800

Solve simultaneous equations:
59L + 59U = 139712
so 19L = 18088
L = 952
U = 2368 - 952 = 1416

952 lower level tickets and 1416 upper level tickets were sold.
3 0
3 years ago
Please this is urgent I need help please answer me
Verizon [17]

Answer:

u have the answer yet?

Step-by-step explanation:

?

8 0
3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

5 0
3 years ago
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