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3 years ago

Solve the equation below. 2.3=p+0.6p=

Mathematics

1 answer:

Bas_tet [7]3 years ago

8 0

Answer:

p=1.4375

Step-by-step explanation:

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Question 1<br> Simplify<br> √-100?

Hitman42 [59]

Answer:

√100 = 10

so √-100 =

i√10

6 0

3 years ago

Helpppp please anyone. I don't understand

vovikov84 [41]

The area is 21cm squared. u would have to find the length of the bottom triangle which is 14. than multiply that by the height which is 3. finally divide that all by 2 and youll get the area

7 0

3 years ago

Question 1 (1 point)

Naily [24]

Answer:

P ( -1, -3)

Step-by-step explanation:

Given ratio is AP : PB = 3 : 2 = m : n and points A(5,6) B(-5,-9)

We will calculate coordinates of the point P which divides line segment AB in the following way:

xp = (n · xa + m · xb) / (m+n) = (2 · 5 + 3 · (-5)) / (3+2) = (10-15) / 5 = -5/5 = -1

xp = -1

yp = (n · ya + m · yb) / (m+n) = (2 · 6 + 3 · (-9)) / (3+2) = (12-27) / 5 = -15/5 = -3

yp = -3

Point P( -1, -3)

8 0

3 years ago

A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex

kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

$325 mg + 2mg+15 mg=342 mg$

The percentages of each component in the formula are:

Acetaminophen: $\frac{325mg*100}{342mg}=95.03$ %

Chlorpheniramine maleate: $\frac{2mg*100}{342mg} =0.58$ %

Dextromethorphan hydrobromide: $\frac{15mg*100}{342mg}=4.39$ %

If 1 Kg= $10^{6}$ mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

$\frac{10^{6} mg *0.58}{95.03}=6153.85 mg$

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

$\frac{10^{6}mg*100}{95.03}=1052307.7mg$