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My name is Ann [436]
3 years ago
12

In each case, lifting or pushing, why must you exert a force to move the object? Q1-2: How much more effort is required to lift

or push two bricks or masses instead of just one?
Physics
1 answer:
musickatia [10]3 years ago
4 0

Answer:

  1. Newton's first law applies. An object at rest will stay that way until a force is applied.
  2. Any amount of effort can be applied to any amount of mass (in the ideal case). The question is not sufficiently specific.

Explanation:

A force is required to move an object because the object will stay at rest until a force is applied.

__

The effort required to lift or push two masses instead of one depends on the desired effect. For the same kinetic energy, no more effort is required. For the same momentum, half the effort is required for two masses. For the same velocity, double the effort is required.

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I think its b but not sure
3 0
3 years ago
All Houston Methodist buildings system wide have an emergency power generator that turns on to supply emergency power after norm
lesya692 [45]

Answer:

D. 10 seconds

Explanation:

All Houston Methodist Hospital buildings employs the use of EPSS(Emergency Power Supply System). This system employs the use of an emergency power generator that turns on to supply emergency power after normal power shuts down within 10 seconds during power outage.

Due to it being used in a hospital the importance of this emergency power system cannot be overemphasized as it is used to provide power supply to hospital equipment such as life support machines etc.

3 0
3 years ago
Suppose we could shrink the Earth without changing its mass. At what fraction of its current radius would the free-fall accelera
spin [16.1K]

Answer:

R' = \frac{1}{\sqrt{3}}R

Explanation:

The acceleration due to gravity on the surface of the Earth is given by:

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the mass of the Earth

R is the radius of the Earth

Here we want to find the new Earth radius R' for which the gravitational acceleration at the surface, g', would be 3 times the current value of g:

g' = 3g

So we would have

\frac{GM}{R'^2}=3(\frac{GM}{R^2})

Solving the equation for R', we find

R'^2 = \frac{1}{3}R^2\\R' = \frac{1}{\sqrt{3}}R

7 0
3 years ago
Read 2 more answers
Is it possible for the velocity of an object to be zero and its acceleration not zero?
Nesterboy [21]

Explanation:

Yes, it is possible to have zero speed while accelerating, but only for a moment. ... acceleration is the rate at which the speed and direction of an object changes over time, so whenever an object goes through zero speed while reversing directions, it has non-acceleration. zero but a speed of zero.

8 0
3 years ago
Physical science!!!!!!helpppp
ipn [44]

Answer:

Option B

10.36 m/s

Explanation:

Using the first given equation, then velocity=distance/time

Since distance is provided as 200 m and time, t is 19.3 seconds then substituting these figures yields

v=200/19.3=10.3626943

Rounding off to 2 decimal places, then

v=10.36 m/s

6 0
3 years ago
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