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4 years ago

Which plot correctly shows the velocity of the two balls as a function of time?

Physics

1 answer:

yanalaym [24]4 years ago

5 0

The given in this problem is that two balls are thrown at different times, different heights and velocities. A blue ball is thrown upward at a specific velocity at a lower altitude while a red ball is thrown downwards at a specific speed and at a higher height. In this case, we are asked here to describe the graph of the behavior of the balls as a function of time. The x-axis then is time while the y-axis is the velocity of the ball. The blue ball has a quadratic function while the red ball is more or less exponential. See the attached figure for reference.

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1. Place these unknown pH test papers in order from most acidic to most alkaline.

Naddika [18.5K]

Answer: B

Explanation: look at the chart, easy

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3 years ago

A sealed test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18°C. The test tube’s stopper has a diamet

puteri [66]

Answer:

180° C

Explanation:

First we start by finding the area of the stopper.

A = πd²/4, where d = 1.5 cm = 0.015 m

A = 3.142 * 0.015² * ¼

A = 1.767*10^-4 m²

Next we find the force on the stopper

F = (P - P•)A, where

F = 10 N

P = pressure inside the tube,

P• = 1 atm

10 = (P - 101325) * 1.767*10^-4

P - 101325 = 10/1.767*10^-4

P - 101325 = 56593

P = 56593 + 101325

P = 157918 Pascal

Now, remember, in an ideal gas,

P1V1/T1 = P2V2/T2, where V is constant, then we have

P1/T1 = P2/T2, and when we substitute the values, we have

101325/(273 + 18) = 157918/ T2

101325/291 = 157918/ T2

T2 = (157918 * 291)/101325

T2 = 453 K

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3 0

4 years ago

When two plates of differing densities collide, how might the density of each plate affect which plate is pulled beneath the oth

OlgaM077 [116]

Pull the plates apart and you will knwo what it is lmaoo

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3 years ago

A student drops a 1.5 kg rock off of a 4.0 m tall bridge. The speed of the rock just before it hits the water below is 6 m/s. Ho

olga nikolaevna [1]

Answer:

Energy due to air resistance = 31.8 Joules

Explanation:

According to the law of conservation of energy, energy can neither be created nor destroyed but can be transformed from one form to another

Kinetic Energy + Energy due to air resistance = Potential energy..........(1)

If there is no energy loss due to air resistance, potential energy = kinetic energy

mass, m = 1.5 kg

height, h = 4.0 m

speed, v = 6 m/s

Kinetic energy = 0.5 mv²

Kinetic energy = 0.5 * 1.5 * 6²

Kinetic energy = 27 Joules

Potential Energy = mgh

Potential energy = 1.5 * 9.8 * 4

Potential energy = 58.8 Joules

From equation (1)

27 + Energy due to air resistance = 58.8

Energy due to air resistance = 58.8 - 27

Energy due to air resistance = 31.8 Joules

8 0

3 years ago

Read 2 more answers

(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th

Ghella [55]

Answer:

Assuming that the vertical speed of the ball is 14 m/s we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

Explanation:

a) Assuming that the vertical speed is 14 m/s (founded in the book) the initial speed of the ball can be calculated as follows:

$V_{f}^{2} = V_{0}^{2} - 2gh$

Where:

$V_{f}$ : is the final speed = 14 m/s

$V_{0}$ : is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

$V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s$

b) The maximum height is:

$V_{f}^{2} = V_{0}^{2} - 2gh$

$h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m$

c) The time can be found using the following equation:

$V_{f} = V_{0} - gt$

$t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s$

d) The flight time is given by:

$t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s$

I hope it helps you!

3 0

4 years ago