It is now virtually certain that the dominant cause of recent ice ages is

Two objects each moving with speed v travel in opposite directions along a straight line passing through both their centers. The

Tpy6a [65]

Answer:

$\dfrac{1}{16}$

$\dfrac{5}{3}$

Explanation:

$m_1$ = Mass of first object

$m_2$ = Mass of second object

v = Speed of both objects

$\dfrac{v}{4}$ = Combined velocity

The ratio of final kinetic energy to initial kinetic energy will be

$\dfrac{K_f}{K_i}=\dfrac{\dfrac{1}{2}(m_1+m_2)(\dfrac{v}{4})^2}{\dfrac{1}{2}(m_1v^2+m_2v^2)} \\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{v^2}{16}}{m_1v^2+m_2v^2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{1}{16}}{m_1+m_2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{1}{16}$

The ratio is $\dfrac{1}{16}$

As the linear momentum is conserved

$m_1v-m_2v=(m_1+m_2)\dfrac{v}{4}\\\Rightarrow m_1-m_2=(m_1+m_2)\dfrac{1}{4}$

Divide by $m_2$ on both sides

$\dfrac{m_1}{m_2}-1=\dfrac{m_1}{4m_2}+\dfrac{1}{4}\\\Rightarrow \dfrac{m_1}{m_2}-\dfrac{m_1}{4m_2}=\dfrac{1}{4}+1\\\Rightarrow \dfrac{3m_1}{4m_2}=\dfrac{5}{4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5\times 4}{3\times 4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5}{3}$

The ratio of mass is $\dfrac{5}{3}$

6 0

3 years ago

I'll mark brainliest if you help me. :)

BaLLatris [955]

Answer:

gravitational potantional energy

Explanation:

ill try to link a source!

edit: https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/14.3/primary/lesson/potential-energy-ms-ps#:~:text=Potential%20energy%20due%20to%20the,is%20called%20gravitational%20potential%20energy.

3 0

3 years ago

A 67.3-kg climber is scaling the vertical wall of a mountain. His safety rope is made of a material that, when stretched, behave

Monica [59]

Answer:

$d=0.59m$

Explanation:

From the question we are told that:

Mass $m=67.3 kg$

Spring constant $\mu=1.23 * 10^3 N/m$

Fall Height $h=0.921m$

Generally the Energy theorem equation for momentum is mathematically given by

Change in KE=Work done by gravity + work done by spring

$0=mg*(h + d) - \frac{\mu d^2}{2}$

$0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}$

$0=608.1-660.213d-615d^2$

Solving Quadratic equation

$d=0.59m$

8 0

3 years ago

A force of 900 N pushes a wedge 0.10 m into a log. If the work done on the log is 50 J, what is the efficiency of the wedge?

Anna [14]

Answer:

55.56%

Explanation:

We'll begin by calculating the work done in pushing the wedge. This can be obtained as follow:

Force (F) = 900 N

Distance (s) = 0.1 m

Workdone (Wd) =..?

Wd = F × s

Wd = 900 × 0.1

Wd = 90 J

Finally, we shall determine the efficiency. This can be obtained as follow:

Work output = 50 J

Work input = 90 J

Efficiency =?

Efficiency = work output / work input

Efficiency = 50 / 90 × 100

Efficiency = 55.56%

Thus, the efficiency is 55.56%

8 0

3 years ago

Indicate whether the statement is true or false. If false, change the identified word or phrase to make me su

Elza [17]

V = wf
ex) 5m • 16 Hz = 80 m/s
5m • 20 Hz = 100 m/s
Answer : True because when multiplying the same wavelength with an increase in frequency, will give you a higher velocity (speed).

5 0

3 years ago

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