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tekilochka [14]
2 years ago
5

emily paints at a constant rate. she can paint 32 square feet in 5 minutes. what area,A, in square feet, can she paint in t minu

tes? a. write the linear equation in two variables that represents the number of square feet Emily can paint any given time interval.
Mathematics
1 answer:
Paha777 [63]2 years ago
3 0

Answer: A(t) = (6.4 ft^2/min)*t

Step-by-step explanation:

We know that Emily paints at a constant rate, and she can paint 32 ft^2 in 5 minutes.

Then if we take the quotient of these two quantities, we will find the amount she can paint in one minute, this is:

32ft^2/5min = (32/5) ft^2/min = 6.4 ft^2/min.

Then if she paints for t minutes, the area that she can cover can be written as:

A(t) = (6.4 ft^2/min)*t

This is the linear equation we wanted to find.

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The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?
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Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

<u><em>Step 1: You need to create a equation first:</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

<u><em>How did I make the equation?</em></u>

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13  ALL CONSECUTIVE ODD NUMBERS

<u><em>Step 2: Simplifying the equation</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

<u><em>Step 3: Solving the equation, with explanation</em></u>

5n + 20 = 2555       Subtract 20 on both sides

        5n = 2535        Isolate the variable by dividing 5 on both sides

          n = 507

<u><em></em></u>

<u><em>Step 4: Plug in the value</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8

507,  507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

<u><em>Step 5:  Solve the sum of the first, third, and last integer</em></u>

507 + 511 + 515 = 1533

<u><em>Step 6: THE ANSWER</em></u>

1533

<h3><u><em>Hope this helps!!! </em></u></h3><h3><u><em>Please mark this as brainliest!!! </em></u></h3><h3><u><em>Thank You!!! </em></u></h3><h3><u><em>:)</em></u></h3>
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