Firstly need to determine the empirical formula of the hydrocarbon. Empirical formula is the simplest whole number ratio of components of the compound. Molecular formula is the actual composition of the components in the compound.
percentage of C - 82.66%
percentage of H - (100-82.66) = 17.34 %
in 100 g of compound ;
mass of C - 82.66 g
mass of H - 17.34 g
C H
mass in 100 g 82.66 g 17.34 g
molar mass 12 g/mol 1 g/mol
number of moles 6.88 mol 17.34 mol
(mass/molar mass)
divide the number of moles by least number of moles (6.88 mol)
6.88 mol/6.88 17.34/6.88
1 2.52
multiply these by 2 to get a whole number
C - 1x 2 = 2
H - 2.52 x 2 = 5.04
round off to nearest whole number
C - 2
H - 5
ratio of C to H is 2:5
empirical formula - C₂H₅
empirical formula mass = 12 g/mol x 2 + 5 * 1 g/mol = 29 g
next have to find how many empirical units are there in the molecular unit
molecular unit mass = 58.12 g
empirical unit = 29 g
then number of empirical units = 58.12 / 29 = 2
rounded off , number of empirical units = 2
(C₂H₅) * 2 units
molecular formula = C₄H₁₀
Explanation:
Answer:
A
Explanation:
the tendency of a material to conduct heat or electricity can be detected on the outside
<h2>Balance Chemical Equation</h2>
1. N2 + 3 H2 = 2 NH3
2. 2 KCIO3 = 2 KCI + 3 O2
3. 2 NaCI + F2 = 2 CI + 2 NaF
4. 2 H2 + O2 = 2 H2O
5. Pb(OH)2 + 2 HCl = 2 H2O + PbCl2
6. 2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3
7. CH4 + 2 O2 = CO2 + 2 H2O
8. C3H8 + 5 O2 = 3 CO2 + 4 H2O
9. 2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
10. FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl
11. 4 P + 5 O2 = 2 P2O5
12. 2 Na + 2 H2O = 2 NaOH + H2
13. 2 Ag2O = 4 Ag + O2
14. S8 + 12 O2 = 8 SO3
15. 6 CO2 + 6 H2O = C6H12O6 + 6 O2
16. 2 K + MgBr2 = 2 KBr + Mg
17. 2 HCl + CaCO3 = CaCl2 + H2O + CO2
18. HNO3 + NaHCO3 = NaNO3 + H2O + CO2 - already balanced
19. 2 H2O + O2 = 2 H2O2
20. 2 NaNO3 + H2SO4 = Na2SO4 + 2 HNO3
