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Bumek [7]
3 years ago
8

Which is a renewable resource?A.gold B.copper C.timber D.natural gas

Chemistry
1 answer:
romanna [79]3 years ago
7 0

Answer: D. Natural Gas

Explanation:

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An element has an atmomic number of 68. The number of protons and electron in a neutral atom of the element are?
Bess [88]

Answer:

Explanation:

An element whose atomic number is 68 (number Z), has 68 electrons and 68 protons. According to the periodic table it corresponds to the element Erbium (Er), whose mass number (A) is 167. The number of neutrons is 167-68 = 99.

8 0
4 years ago
What is the highest principal energy level for an electron in an atom of sulfur in the ground state?
adoni [48]
<span>The number of valence electrons from the electron configuration,write 1s², 2s² 2p⁶, 3s² 3p⁴.
The "big" numbers are the principal quantum numbers (n) which correspond to the major energy levels, and sub-scripted numbers are the number of electrons in the sub-energy level.
</span><span>For sulfur, the highest principal quantum number is 3, and there are 6 electrons in the 3s² and 3p⁴ sublevels. </span>
6 0
3 years ago
Pls help I’m in a test plssss
____ [38]

Answer:

6

Explanation:

6

5 0
3 years ago
A decomposition reaction is when a substance ____________ down into two or more simpler substances in a chemical reaction.
stiks02 [169]

Apex unfortunately will probably make you get it wrong without adding an "s" into the word break. So if it happens, the answer will be <u>breaks</u>

3 0
3 years ago
A turbine operating adiabatically is fed with steam at 400 °C and 8.0 MPa at the rate of 1000 kg/h. Process steam saturated at 0
Arturiano [62]

Explanation:

We select the enthalpy of steam at state 1 at 800^{o}C and 8.0 MPa from the steam tables as follows.

                     h_{1} = 3138 kJ/kg

Also, we select the enthalpy of steam at state 2 at 0.5 MPa from the steam tables as follows.

                     h_{2} = 2748.6 kJ/kg

At state 3 also, from the steam tables at state 3 at 0.1 MPa.

                     h_{3} = 2675.1 kJ/kg

Hence, calculate the mass flow rate at state 3 as follows.

                  m_{3} = m_{1} - m_{2}

                              = 1000 kg/h - 300 kg/h

                              = 700 kg/h

Now, we will calculate the power output of the turbine as follows.

                 W_{r} = m_{1}(h_{1} - h_{2}) + m_{3}(h_{2} - h_{3})

                             = 1000 kg/h (3138 kJ/kg - 2748.6 kJ/kg) + 700 kg/h (2784.6 kJ/kg - 2675.1 kJ/kg)

                            = 440850 kJ/h

It is known that 1 kJ/h = 0.000278 kW.

Therefore,        440850 kJ/h \times \frac{0.000278 kW}{1 kJ/hr}    

                          = 122.56 kW

Thus, we can conclude that the power output of the turbine is 122.56 kW.

6 0
3 years ago
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