All categories

3 years ago

Brooke solved the equation below:

1 answer:

8 0

No. 6r is 6 multiplied by r so in order to get r, you will need to divide both sides by 6 in the first equation so r should =12

You might be interested in

A 12 oz bottle of BBQ sauce sells for $ 4.20. How much one oz of sauce cost?

Studentka2010 [4]

Answer:

0.35

Step-by-step explanation:

it's just 4.20÷12=0.35

5 0

3 years ago

Given vectors a=(1,2), b=(2,-1), find 4a-3b

riadik2000 [5.3K]

A=(1,2) and b=(2, - 1) . Find 4a - 3b

1st carry out the scalar multiplication 4a and -3b

4a =[4(1) , 4(2) ] = (4 , 8)

-3b = [-3(2) . -3(-1)] = (-6 , +3)

4a - 3b = [(4-6) , (8+3)] = (-2 , 11)

3 0

3 years ago

What does mean median mode and range mean in math terms?

Sergeu [11.5K]

Mean : add all the numbers and divide by how many numbers their are.
median: arrange the numbers greatest to least (or vice versa) and find the middle number.
mode: which set of numbers shows up the most often
range: subtract the smallest number from the largest number

3 0

4 years ago

What is the equation of the line that passes through (0, -2) and has a slope of O?

Dmitriy789 [7]

Answer:

The equation of the line that passes through (0, -2) and has a slope of 0 is $\mathbf{y=-2}$

Step-by-step explanation:

We need to find the equation of the line that passes through (0, -2) and has a slope of 0?

The equation of line can be expressed in slope-intercept form $y=mx+b$ where

m is slope
b is y-intercept

We need to find slope and y-intercept for the equation.

We are given slope = 0 so, m = 0

Now, y-intercept can be found using slope m=0 and point (0,-2)

$y=mx+b\\-2=0(0)+b\\-2=b\\or\\b=-2$

So, we get y-intercept: b = -2

Now, the equation of the line having slope m=0 and y-intercept b=-2 is:

$y=mx+b\\y=0(x)-2\\y=-2$

So, the equation of the line that passes through (0, -2) and has a slope of 0 is $\mathbf{y=-2}$

5 0

3 years ago

HELP PLEASE!!!!! Solve each system.

Ede4ka [16]

$15.\ \text{Elimination method}\\\underline{+\left\{\begin{array}{ccc}y=-3x+9\\y=3x+3\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2y=12\qquad\text{divide both sides by 2}\\.\qquad \boxed{y=6}\\\\\text{put the value of y to the second equation}\\\\6=3x+3\qquad\text{subtract 3 from both sides}\\3=3x\qquad\text{divide both sides by 3}\\1=x\to\boxed{x=1}\\\\Answer:\ x=1,\ y=6\to(1,\ 6)$

$16.\ \text{Substitution method}\\\left\{\begin{array}{ccc}y=11x+4\\y=7x-16\end{array}\right\Rightarrow11x+4=7x-16\\\\11x+4=7x-16\qquad\text{subtract 4 from both sides}\\11x=7x-20\qquad\text{subtract 7x from both sides}\\4x=-20\qquad\text{divide both sides by 4}\\\boxed{x=-5}\\\\\text{Put the value of x to the first equation}\\\\y=11(-5)+4\\y=-55+4\\\boxed{y=-51}\\\\Answer:\ x=-5,\ y=-51\to(-5,\ -51)$

7 0

4 years ago

Read 2 more answers