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asambeis [7]
3 years ago
10

A short note on Artificial rain (100-150 words)

Chemistry
2 answers:
katovenus [111]3 years ago
8 0

Answer:

Artificial rain a practice of artificially inducing or increasing precipitation through clouds by adding external agents. The foreign particles which are drenched over these clouds can be Dry Ice(solid carbon dioxide), Silver Iodide, Salt powder etc. This process is known as Cloud Seeding. It is weather modification by dispersing substances into the air that served as clod condensation or ice nuclei. Harmful effects of this are as follow, Silver iodide used for such rain can cause temporary incapacitation in mammals. It was invented by VINCENT SCHAEFER.

Wewaii [24]3 years ago
5 0
It’s a practice of artificially inducing or increasing precipitation through clouds by adding external agents.

The foreign particles which are drenched over these clouds can be Dry Ice(solid carbon dioxide), Silver Iodide, Salt powder etc. This process is known as Cloud Seeding. This stimulation is done by aeroplanes or rockets. And then finally "rain on".

Agitation : The first stage includes the use of chemicals to stimulate the air mass upwind of target area to rise and form clouds. These chemicals absorbs the water vapour and helps in the process of condensation. Chemicals like - Calcium Oxide, compound of Urea and Ammonium Nitrate or Chloride Calcium Carbonate.

Building Up Stage : In the second stage the mass of the cloud is build up by urea, dry ice, kitchen salt etc to increase the density of the clouds.

Seeding : In the final stage of persuing the artificial rain, super cool chemicals (dry ice or iodide) are bombarded with the presurized canister onto the base of the clouds to build the beads of water and make them fall as rain.


HOPE IT HELPS!!!!!
MARK ME THE BRAINLIEST!!!!!!
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Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
coldgirl [10]

Answer:

\rm_{90}^{231}\text{Th}

Explanation:

The unbalanced nuclear equation is

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

 92 = 2 + Z , so  Z =   92 - 2 =  90

And your nuclear equation becomes

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

Element 90 is thorium, so  

\rm X = _{90}^{231}\text{Th}

7 0
3 years ago
A galvanic^cell consists of left ompartmcnt with a tin elcctrode in contact with 0.1 M Sn(NO_3)_2(aq) and a right compartment wi
lana66690 [7]

Answer:

Electrons will flow from left to right through the wire.

Pb^2+ ions will be reduccd to Pb metal.

The concentration of Sn2+ ions in the left compartment will increase.

Explanation:

Looking at the relative electrode potentials of the two metals

Sn= -0.14

Pb=-0.13

Tin is expected to function as the anode (left hand half cell) and lead as the anode (right hand half cell) tin oxidizes to sn^2+ hence its concentration increases on the left compartment while lead is reduced to ordinary lead metal on the right hand half cell . since oxidation occurs on the left hand side, electrons flow from left to right.

6 0
3 years ago
Suppose you are a member of your city planning board. A company wants to build a large shopping mall near a river in your area.
Flura [38]
A should be the answer.
8 0
3 years ago
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When you light a fire place what energy transformation takes place
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Heat energy is released to warm the house
3 0
3 years ago
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The density of air at ordinary atmospheric pressure and 25 ∘C is 1.19 g/L. What is the mass, in kilograms, of the air in a room
marshall27 [118]
Given:
The density of air = 1.19 g/L at 25°C and atmospheric pressure,
or
density = 1.19 x 10⁻³ kg/L

Volume of air in the room is
V = 12.5*19.5*6.0 = 1462.5 ft³

Note that
1 ft³ = 28.317 L
Therefore
V = (1462.5 ft³)*(28.317 L/ft³) = 4.1414 x 10 ⁴ L

By definition, mass = density*volume.
Therefore, the mass is
(1.19 x 10⁻³ kg/L)*(4.1414 x 10⁴ L) = 49.283 kg

Answer: 49.3 kg (nearest tenth)
7 0
3 years ago
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