Answer:
Explanation:
The car is rolling without slipping so Vcm= R×ω = 0.325×49 = 16
First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
<h3>
First harmonic of a closed pipe</h3>
The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.
L = λ/4
where;
- L is the length of the pipe
- λ is the wavelength of sound
λ = 4L
But, v = F₀λ
v = F₀(4L)
F₀ = v/4L
where;
- F₀ is the first harmonic
- v is speed of sound
Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
Learn more about fundamental frequency here: brainly.com/question/1967686
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<h3 />
Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N
Explanation:
- Acceleration is the rate of change of velocity.
- It is given by the equation, a = change in velocity/time
Here, velocity changes from 0 to 27 m/s and time = 8
⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²
- Force is calculated by the equation, F = Mass × Acceleration
- This is based on Newton's second law of motion.
Here, mass of the car = 1500 kg and a = 3.375 m/s²
⇒ Force = 1500 × 3.375 = 5062.5 N
Speed = 22.8m/min
= 22.8 / 60
=0.38m/s
time = distance/ speed
= 467/0.38
= 1252.63s
