Answer:
<em>a) -1.125q</em>
<em>b) -3q</em>
<em>c) -3q</em>
<em></em>
Explanation:
The discs are A, B, and C
Their charges are;
A = 2q
B = -5q
C = 0q
In the first quarter of the game the opposing team is able to touch disc A and B together then separate them. This leaves a net charge of
= -1.5q on each of the discs A and B.
Then the home team scores by touching disc C to disc A and then separates them. This leaves a charge of
= -0.75q on the discs C and A.
Finally, the opposing team scores again by touching disc C to disc B and then separates them. This leaves a charge of
= -1.125q on the discs C and B
a) the final charge of object C = <em>-1.125q</em>
b) Before the objects touch, their total charge = 2q + (-5q) + 0q = <em>-3q</em>
c) After the objects touch, their total charge = (-0.75q) + (-1.125q) + (-1.125q) = <em>-3q</em>
Answer:
Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.
Explanation:
The distance from the central band to the first bright band is given by
where is the wavelength of light (or any particle), is the distance to the screen, and is the slit separation.
From this equation we see that, by increasing the wavelength , increasing the distance from the screen , and decreasing the slit separation , we increase the distance between the first bright band and the central band.
Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
Read more on Brainly.com -
brainly.com/question/1581851#readmore
Answer:
F=(-4.8*10^22,0,0) N
Explanation:
<u>Given :</u>
We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°
Solution :
We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.
The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next
F=|F|cosФp (1)
Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet
F=|F|cosФp
=-4.8*10^22 N*p
<em>As this force is in one direction, we could get its vector as next </em>
F=(-4.8*10^22,0,0) N
F=(0,-4.8*10^22,0) N
F=(0,0-4.8*10^22) N
The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.
Question:
How do mountain glaciers and continental glaciers differ in terms of dimensions, thickness and patterns of movement?
Answer:
<span>
Continental glaciers are thicker, much more expansive sheets. Mountain glaciers flow downhill as a result of gravity acting on the mass of ice. Continental glaciers move in response to pressure from the weight of material in their thick midsections.
</span>
Hope this helped!
~Shane :}