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3 years ago

What is two fifths of 60

2 answers:

6 0

2/5 of 60=24. Usually when you see the word "of" it means to multiply. So multiply 2/5 times 60/1 (this is still 60) straight across. If you multiply correctly you should get 120/5 then you just divide 120 by 5. What you should get is 24. Hope I could help.

exis [7]3 years ago

4 0

Easy. that is 24. if you divide 2/5 of 60...well u just need to know that it is 24

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At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up t

klemol [59]

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3 years ago

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I need help solving it

blagie [28]

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An individual who has automobile insurance from a certain company is randomly selected. Let y be the number of moving violations

Hoochie [10]

Answer:

a) $E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

b) $E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Solution to the problem

Part a

We have the following distribution function:

Y 0 1 2 3

P(Y) 0.45 0.2 0.3 0.05

And we can calculate the expected value with the following formula:

$E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

Part b

For this case the new expected value would be given by:

$E(80Y^2)= \sum_{i=1}^n 80Y^2_i P(Y_i)$

And replacing we got

$E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

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Part e because I did it and got it right on the test txt me if u need help

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