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3 years ago

Calculate by how much a spring with spring constant 1.2N/m has been squashed when it has stored 76J,

Physics

1 answer:

fgiga [73]3 years ago

7 0

Answer:

11.25 m

Explanation:

From the question given above, the following data were obtained:

Spring constant (K) = 1.2 N/m

Energy (E) = 76 J

Compression (e) =?

Energy stored in a spring is given by the following equation:

E = ½Ke²

Where:

E => Energy stored in the spring.

K => spring constant

e => Extention or compression

With the above formula, we can obtain how much the spring has been squashed as follow:

Spring constant (K) = 1.2 N/m

Energy (E) = 76 J

Compression (e) =?

E = ½Ke²

76 = ½ × 1.2 × e²

76 = 0.6 × e²

Divide both side by 0.6

e² = 76 / 0.6

Take the square root of both side.

e = √(76 / 0.6)

e = 11.25 m

Thus, the spring has been squashed by 11.25 m

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4 years ago

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Answer:

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