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Natasha_Volkova [10]
3 years ago
8

1. On which date does the Antarctic Circle have 24 hours of daylight? A. June 21

Physics
2 answers:
pashok25 [27]3 years ago
6 0

1. On which date does the Antarctic Circle have 24 hours of daylight?

the answer is D

2. when energy is transferred to air, what happens to the particles of Air?

the answer is B

HOPE THIS HELPED

sattari [20]3 years ago
5 0
The date in which the Antarctic Circle has 24 hours of daylight on December 21st every year. When energy is transferred to air the particles of air become more excited and move around faster.
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Un avión que sale del aeropuerto de mexico a las 7 horas con o min aterriza en la ciudad de Bogotá, Colombia a las 11 horas con
Vitek1552 [10]

4095km

Explanation:

Given parameters:

Starting time = 7 o'clock

Stopping time = 11hrs 30min

Speed  = 910km/hr

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

It is a scalar quantity that is with respect with magnitude but no direction.

 Speed = \frac{distance}{time}

 Distance = Speed x time

Time taken = time between 11hrs 30min and 7 o'clock = 4.5hrs

  Input the parameters:

  Distance = 910km/hr x 4.5hrs = 4095km

learn more:

Speed brainly.com/question/10048445

#learnwithBrainly

6 0
3 years ago
If two objects have the same volume but one has a greater mass, the one with greater mass
11Alexandr11 [23.1K]

Explain more. I can't understand

7 0
3 years ago
the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67​
baherus [9]

Answer:

\theta_c = 36.78^o

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

\theta_c = Sin^{-1}(\frac{1}{1.67} )

\theta_c = 36.78^o

4 0
3 years ago
Wave interactions
rewona [7]

Hi! I want to know this

6 0
3 years ago
8. A 740 kg car traveling 19 m/s comes to a complete stop in 2.0 s. What is the force exerted on the car during this stop?
zaharov [31]
Force = mass * acceleration 

acceleration = change_in_velocity / time

so:

force = 740 kg * (19 m/s - 0 m/s) / 2.0 s
= 740 * 19 / 2 kg m per second^{2}
= 7030 kg m per second^{2}
= 7030 newtons of force
6 0
3 years ago
Read 2 more answers
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