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Thepotemich [5.8K]

2 years ago

6

What is the mass of an object if a force of 48 Newtons produces an acceleration of 6 m/s2?

1 answer:

Mars2501 [29]2 years ago

6 0

Answer:

m = 8 kg

Explanation:

According to Newton's second law of motion, F = ma.

Solving for m using algebra:

m = F ÷ a

m = 48 N ÷ 6 m/s² = 8 kg

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What is the radius of the event horizon of a 10 solar mass black hole?

deff fn [24]

Answer:

The number take for the "radius" is normally taken to be the radius from the center to the event horizon, since nothing inside that can be observed, and since it is a point of no return. This radius is directly proportional to the mass of the black hole. From the Wikipedia article on event horizon: "For the mass of the Sun this radius is approximately 3 kilometers and for the Earth it is about 9 millimeters. In practice, however, neither the Earth nor the Sun has the necessary mass and therefore the necessary gravitational force, to overcome electron and neutron degeneracy pressure." The last sentence means that it is unlikely for the Sun to become a black hole, since it has too little mass to become one.

Explanation:

CAN I GET BRAINLIEST

6 0

3 years ago

A tsunami, an ocean wave generated by an earthquake, propagates along the open ocean at 700 km/hr and has a wavelength of 750 km

Colt1911 [192]

Answer:

C) 0.00026 Hz

Explanation:

In any wave, there exists a fixed relationship between the speed v, the frequency f and the wavelength λ, as follows:

$v = \lambda * f (1)$

Replacing by the givens in (1), and solving for f, we get:

$f = \frac{v}{\lambda} = \frac{700km/hr}{750 km} = 0.93 1/hr (2)$

Converting the units to Hz (1/sec), we get:

$f = 0.93 \frac{1}{hr} *\frac{1 hr}{3600sec} = 2.6e-4 = 0.00026 Hz (2)$

The answer C. is the right one.

7 0

3 years ago

A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8

mylen [45]

Answer:

$f = 2.6 \times 10^{-13}$

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

$N = \frac{m}{29} \times 6.02 \times 10^{23}$

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

$N_e = m(6.02 \times 10^{29})$

now diameter of the ball is 7.0 mm

density of the ball = $8900 kg/m^3$

now we have

$m = (\frac{4}{3}\pi r^3)(8900)$

$m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)$

$m = 1.6 gram$

now we have

$N_e = 9.63 \times 10^{23}$

now the charge on the copper ball is 40 nC

so the number of electrons removed

$Q = ne$

$40 \times 10^{-9} = n(1.6 \times 10^{-19}$

$n = 2.5 \times 10^{11}$

so the fraction of number of electrons removed is given as

$f = \frac{n}{N_e}$

$f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}$

$f = 2.6 \times 10^{-13}$

7 0

3 years ago

The speed of a car is increased uniformly from 11 meters per second to 19 meters per second. The average speed of the car during

dsp73

15 m/s average is (11+19)/2

6 0

3 years ago

PLEASE HELP!!!!

s2008m [1.1K]

You can download answer here

tinyurl.com/wpazsebu

4 0

3 years ago