The limiting reactant when 5.6 moles of aluminium react with 6.2 moles of water is
water( H2O)
<u><em>Explanation</em></u>
The balanced equation is as below
2 Al +3 H2O → Al2O3 +3 H2
The mole ratio of Al :Al2O3 is 2:1 therefore the moles of Al2O3
= 5.6 x1/2 = 2.8 moles
The mole ratio of H2O: Al2O3 is 3:1 therefore the moles of Al2O3 produced
= 6.2 x1/3= 2.067 moles
since H2O yield less amount of Al2O3 , H2O is the limiting reagent.
2H2O=2H2+O2
37.4g H2O(1 mol/18.02)=2.07547 mol H2O
PV=nRT
(1.30)(V)=(2.07547)(.0821)(297)
Vwater=38.92898L
38.92898L (1 mol O2/2 mol H2O)=19.46449L O2 gas
Answer:
C₆H₈O₆
Explanation:
The molecular formula of given compound is C₆H₈O₆. Because there are six carbon, six oxygen and eight hydrogen atom present in this compound.
The molecular weight of following compound is,
C₆H₈O₆
C = 12 amu
H = 1 amu
O = 16 amu
C₆H₈O₆ = 12×6 + 1×8 + 16×6
C₆H₈O₆ = 72 +8 + 96
C₆H₈O₆ = 176 g/mol
