Question

A cylinder, with a piston pressing down with a constant pressure, is filled with 2.10 moles of a gas (n1), and its volume is 46.0 L (V1). If 0.700 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?

Answer 1

Answer:

The volume is  $V_2 =15.33 \ L$

Explanation:

From the question we are told that

    The number of moles of the gas is  $n_1 = 2.10 \ moles$

      The volume of the gas is  $V = 46.0 \ L$

        The  of moles of the gas that leaked is  $n_2 = 0.700 \ mol$

Generally from the ideal gas law

      $PV = nRT$        

Generally at constant pressure and temperature

        $\frac{V}{n} = constant$

So   $\frac{V_1 }{n_1} = \frac{V_2 }{n_2}$

=>    $V_2 = \frac{ V_1 * n_2 }{ n_1}$

=>    $V_2 = \frac{ 46.0 * 0.700 }{ 2.10 }$  

=>    $V_2 =15.33 \ L$