Answer:
![\boxed {\boxed {\sf 5.1 \ mol \ H_2O}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%205.1%20%5C%20mol%20%5C%20H_2O%7D%7D)
Explanation:
To convert from representative particles to moles, Avogadro's Number: 6.02*10²³, which tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance.
We can use it in a ratio.
![\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}](https://tex.z-dn.net/?f=%5Cfrac%20%7B6.02%2A10%5E%7B23%7D%20%5C%20molecules%20%5C%20H_2O%7D%7B1%20%5C%20mol%20%5C%20H_2O%7D)
Multiply by the given number of molecules.
![3.1*10^{24} \ molecules \ H_2O*\frac {6.02*10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}](https://tex.z-dn.net/?f=3.1%2A10%5E%7B24%7D%20%5C%20molecules%20%5C%20H_2O%2A%5Cfrac%20%7B6.02%2A10%5E%7B23%7D%20%5C%20molecules%20%5C%20H_2O%7D%7B1%20%5C%20mol%20%5C%20H_2O%7D)
Flip the ratio so the molecules of water cancel out.
![3.1*10^{24} \ molecules \ H_2O*\frac {1 \ mol \ H_2O}{6.02*10^{23} \ molecules \ H_2O}](https://tex.z-dn.net/?f=3.1%2A10%5E%7B24%7D%20%5C%20molecules%20%5C%20H_2O%2A%5Cfrac%20%7B1%20%5C%20mol%20%5C%20H_2O%7D%7B6.02%2A10%5E%7B23%7D%20%5C%20molecules%20%5C%20H_2O%7D)
![3.1*10^{24} *\frac {1 \ mol \ H_2O}{6.02*10^{23} }](https://tex.z-dn.net/?f=3.1%2A10%5E%7B24%7D%20%2A%5Cfrac%20%7B1%20%5C%20mol%20%5C%20H_2O%7D%7B6.02%2A10%5E%7B23%7D%20%7D)
![\frac {3.1*10^{24} \ mol \ H_2O}{6.02*10^{23} }](https://tex.z-dn.net/?f=%5Cfrac%20%7B3.1%2A10%5E%7B24%7D%20%5C%20mol%20%5C%20H_2O%7D%7B6.02%2A10%5E%7B23%7D%20%7D)
Divide.
![5.14950166113 \ mol \ H_2O](https://tex.z-dn.net/?f=5.14950166113%20%5C%20mol%20%5C%20H_2O)
The original number of molecules has 2 significant figures: 3 and 1, so our answer must have the same. For the number we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.
![5.1 \ mol \ H_2O](https://tex.z-dn.net/?f=5.1%20%5C%20mol%20%5C%20H_2O)
There are about 5.1 moles of water in 3.1*10²⁴ molecules of water.
You can use P1V1/T1 = P2V2/T2 but since pressure is constant is becomes V1/T1=V2/T2
V1=0.5 L
T1=203 K
T2=273 K
V2=unknown
0.5L/203 = V2/273
V2= 0.67 L so C
Hope this helps :)
The potential energy ..
1- when a rubber band is stretche and waiting to be released
2- an acorn hanging from a oak tree
3- a pice of celery
I think it’s 7.41 because you count up all the atoms and find out how many are x (the large grey ones) and you do 2/27 x 100 which gives you 7.41 :) (sorry if i counted wrong it’s kinda hard)