Question

What is the measure of ∠JSM? A) 12° B) 17° C) 23° D) 31°

Answer 1

Answer:

Option B.

Step-by-step explanation:

Given information: $m\angle A=48^{\circ},\angle E=90^{\circ},\angle EMS=59^{\circ}$.

According to the angle sum property of a triangles, the sum of interior angles of a triangle is 180°.

Apply angle sum property on triangle AEJ.

$\angle A+\angle E+\angle J=180^{\circ}$

$48^{\circ}+90^{\circ}+\angle J=180^{\circ}$

$138^{\circ}+\angle J=180^{\circ}$

Subtract 138 from both sides.

$\angle J=180^{\circ}-138^{\circ}$

$\angle J=42^{\circ}$

The measure of angle J is 42°.

According to exterior angle property, the sum of two interior angles of a triangle is equal to the third exterior angle.

Apply exterior angle property on triangle JMS.

$\angle EJA+\angle JSM=\angle EMS$

$42^{\circ}+\angle JSM=59^{\circ}$

Subtract 42 from both sides.

$\angle JSM=59^{\circ}-42^{\circ}$

$\angle JSM=17^{\circ}$

The measure of ∠JSM is 17°.

Therefore, the correct option is B.

Answer 2

I think it would be “B”