There are 440 boys and 460 girls
The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:
x+y=18 (because the problem tells you there were 18 cars in total)
3000x+5000y=60000 (because that is the total weight in the problem)
Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.
x=18-y
Then you have to plug that into the other equation to get:
3000(18-y)+5000y=60000
Simplify and solve for y:
54000-3000y+5000y=60000
54000+2000y=60000
2000y=6000
y=3
Now that you know what y equals, you can put it into the equation we solved for x:
x=18-3
x=15
So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.
The first number on the left is always one so 0 is ten because you say 5 is in the ones place and then 0 is in the tenths because you count up by five
Answer:
<h2>u = 0</h2>
Step-by-step explanation:
Answer:
The measure of the angles are 55° and 35°
Step-by-step explanation:
Sum of two angles that are complement of each other are 90.
The angles are A and B, so we can write:
A + B = 90
Also,
The difference is 20. Let A be the greater of them, so we can write equation 2 as:
A - B = 20
Now, we add up both equations, eliminate B and solve for A first:
A + B = 90
A - B = 20
---------------
2A = 90 + 20
2A = 110
A = 110/2
A = 55
And now the measure of B:
A + B = 90
55 + B = 90
B = 90 - 55
B = 35
