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2 years ago

10

What is the generic equation for a combustion reaction?

1 answer:

anastassius [24]2 years ago

5 0

Answer:

The generic equation for a combustion reaction is AB + O2 à AO + BO

Explanation:

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A. A pure chemical substance consisting of one type of atom

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Are properties such as odor, color, density, and solubility physical or chemical properties?

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An object floats im sea water more readily because of sea water’s

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What emotional state is important to maintain while reporting an accident in the lab?

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Two cylinders are made of the same material. Cylinder A is one-fourth (1/4) the length of cylinder B and it has a radius that is

tankabanditka [31]

Answer:

$M_{A}$ : $M_{B}$ = 4 : 1

Explanation:

Given that:

Volume of a cylinder = $\pi$ $r^{2}$ h

For cylinder A, $l_{A}$ = $h_{A}$ = $\frac{1}{4} l_{B}$ and $r_{A}$ = 4 $r_{B}$ .

Volume of cylinder A = $\pi$ $(4r_{B}) ^{2}$ × $\frac{1}{4} l_{B}$

= 4 $\pi$ $r_{B} ^{2}$ $l_{B}$

Volume of cylinder B = $\pi$ $(r_{B}) ^{2}$ $l_{B}$

= $\pi$ $r_{B} ^{2}$ $l_{B}$

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e ρ = $\frac{M}{V}$

Thus, since the cylinders are made from the same material, they have the same density (ρ). So that;

density of A = density of B

density of A = $\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }$

density of B = $\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }$

⇒ $\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }$ = $\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }$

The ratio of mass of cylinder A to that of B is given as;

$\frac{M_{A} }{M_{B} }$ = $\frac{4\pi r_{B} ^{2} l_{B} }{\pi r_{B} ^{2} l_{B} }$

⇒ $\frac{M_{A} }{M_{B} }$ = $\frac{4}{1}$

Therefore, $M_{A}$ : $M_{B}$ = 4 : 1

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